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Knight b6, bishop e7??
1.Qxd3# Just kidding I'm giving up for today. Hopefully someone have solved it when I come back tomorrow.
You should play a legal move.
You can see the full solution tomorrow. I will post it later. Goodnight to you Martino. Thanks for solving.
this position is illegal...
fiction969, show us the moves.
White mates in 2
I worked on this for 2 hours and 15 minutes
Very nice. You may now take a rest.
this is what i got..
1.NxP+ NxN 2. NxP#
You should be more specific, but it's not correct, there's a bishop on a3.
1. Nxf4+...Nxf4 (forced) 2. Ngxe7#
Yah, the author intentionally made this an illegal position. This problem will put the solver's thinking ability to supreme test!! Engines cannot be of help. Cheaters are not welcome here.
Very nice try but: 1. Nxf4+! Nxf4+!! also.
i got ...Rxf4 Nxf4, Nxf4#
black has to take back with the knight
NO. HE. DOESN'T.
In how many posts do I need to point out the bishop?
Thanks for solving. 1. Ngxe7+ Black has to take with the Bishop! ...Bxe7!!
Scottrf, I thought you're out.
Nice one. I have an assistant screening the posts.
Thanks a lot.
I wonder who can solve this very difficult puzzle.
you didn'd state any move black had to make in the question, just a sequence of two moves to mate
which i found
is my amended solution not correct
1. Ngxe7+ Bxe7!!
No, it's not a helpmate puzzle, black wouldn't play Nxf4. Kxe6 maybe.
Hahaha There is no mate in 2, but only mate in 3 (many)
Let's see Miss Qweeni2. I qoute you on that!
We are looking here for a mate in 2 solution, not mate in three. Very difficult isn't it?