very very tough math puzzle

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Avatar of M-Saoud

What number should replace the question mark?

if you like this kind of puzzles join us in "Online Chess School"

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Avatar of M-Saoud

Sorry , the both answers are wrong

Avatar of NewAlchemy98

How do I sign up?

Avatar of Simone070792

I'm going for 52.

Avatar of M-Saoud

sorry Simone  52 is wrong

Avatar of M-Saoud
NewAlchemy98 wrote:

How do I sign up?


 go this link http://www.chess.com/groups/home/online-chess-school  and join the group

Avatar of mann789

 50?..is that correct..

Avatar of abvctf

The correct answer is 14. 

I put some studies here http://www.chess.com/groups/forumview/etuumltbase

and some combinations here and here: (and planning to update them every week)

http://www.chess.com/groups/forumview/mat-kombinezonlar

http://www.chess.com/groups/forumview/haftann-kombinezonlar

Unfortunately they're annotated in my native language, but it may be useful for whoever likes to solve this kind of stuff. Good luck with your newlyfound group BTW.

Avatar of khan_rajesh
[COMMENT DELETED]
Avatar of khan_rajesh

 i think the answer is 45

Avatar of LubenP

Is it 35?

Avatar of Federico3

Is't 32

1) 8+4+1=13 the perfect square nearest to 13 is 16 ... 13+16=29

2) 2+3+4=9  the perfect square nearest to 9 is 9 ... 9+9=18

3) 1+6+9=16 the perfect square nearest to is 16.... 16+16=32

Avatar of Simone070792

45?

Avatar of Supermissile

32! What does this have to do with chess though?Surprised

Avatar of M-Saoud

Accually there is only one of you find the correct answer?

who nominate himself?

Avatar of Bulgemanfoo

52 works mathematically as a relation but you said it was wrong oh well ill explain it anyway if you subtract the perimeter triangles from the center you will get the second highest value squared

Avatar of abvctf

8,4,1--->29   29x29=841

3,2,4--->18    18x18=324

1,9,6--->?     ?x?=196 thus ?=14

Avatar of Simone070792

14 it is then :-)

Avatar of M-Saoud

lol , that's right !!

Avatar of adude23

The problem with this problem is that there's more than 1 answer, depending on how you solve it. Everyone, as long as they had a reason that was without mistake, should be correct.