Weird Grotesque Chess Problem

Boris Sidorov, 1980 Mate in 3.

ok

@ReishiLion

Ulp!

Of course, it can be done more efficiently but everyone loves the black full house.

This position can be reached after black has accepted the notorious Punkybrewster-Roosterblooper gambit, if black continues not to develop well. You can see that although black has a lead in material, many of their pawns are doubled. White's pawn, meanwhile, is more active and one square away from promotion. Black has not only struggled to regain the center of the board after accepting the Punkybrewster-Roosterblooper gambit, but many of black's pieces are smothered behind their own pawn structure. As is typical in these sorts of gambits, white has traded some pieces for a strong positional advantage. Although it may not be obvious at first glance, white is actually winning this game. 

1) Ke2??? f1=Q+ 2) Kxf1 Ba5+ and Black wins.

You may want to remove your answer so that others can still search.

ok sry

You may want to remove your answer so that others can still search.

okay thank you I will remove it now

The Punkybrewster-Roosterblooper gambit does not exist? Another weird conspiracy theory. Last week I spoke with the gambits inventor John Roosterblooper and his wife Mary Punkybrewster on their return from the Marsian valley of the mask where they played in he 3rd edition of the Punkybrewster-Roosterblooper gambit tournament. As usual Saturn's Punkybrewster-Roosterblooper gambit champion won the event but John and Mary ended honorably 2nd in the Punkybrewster-Roosterblooper gambit competition for pairs. Not just the players come in pairs, the checkmates have to be handed out in pairs as well. Here is an example:

I think the Punkybrewster-Roosterblooper Gambit doesn't exist.

With a diagram now showing the solution (and after overlooking that it was actually the O.P. that gave the solution) I am not going to bother asking anyone else to hold off so that people can solve it for themselves.

correct!!!!! found the rook underpromotion.