The problem is that 0.99 repeating isn’t a real number. Your proof, One_Zeroith, assumes that the 9’s never actually reach an actual infinite. You assume they keep increasing when you keep checking, which wouldn’t be the case when the number of nines is actually infinite.
0.999...ad infinitum does NOT Equal 1!
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Lincoy3304 wrote:
The problem is that 0.99 repeating isn’t a real number. Your proof, One_Zeroith, assumes that the 9’s never actually reach an actual infinite. You assume they keep increasing when you keep checking, which wouldn’t be the case when the number of nines is actually infinite.
10-(1/infinity) is not 10
Lincoy3304 wrote:
One_Zeroth wrote:
He totally discounted my demonstration, and provided nothing new, at all.
If there are two contradictory proofs that are completely logical, the answer to which proof is correct is meaningless - the question is unsolvable.
Wha??
One_Zeroth wrote:
Lincoy3304 wrote:
The problem is that 0.99 repeating isn’t a real number. Your proof, One_Zeroith, assumes that the 9’s never actually reach an actual infinite. You assume they keep increasing when you keep checking, which wouldn’t be the case when the number of nines is actually infinite.
10-(1/infinity) is not 10
Show me
One_Zeroth wrote:
Lincoy3304 wrote:
One_Zeroth wrote:
He totally discounted my demonstration, and provided nothing new, at all.
If there are two contradictory proofs that are completely logical, the answer to which proof is correct is meaningless - the question is unsolvable.
Wha??
This is what has happened in multiple problems in set theory, and is widely accepted. If there are no incorrect proofs presented, and the proofs lead to different, unresolvable results, then the problem is considered meaningless unless one can show that one of the proofs is wrong and the other correct.
Wha?
99
He totally discounted my demonstration, and provided nothing new, at all.
If there are two contradictory proofs that are completely logical, the answer to which proof is correct is meaningless - the question is unsolvable.