An infinity number of 9's written without a decimal point, say n 9's will never be 10^n, always just (10^n)-1
Case closed!
You are mistaken. You cannot write an infinite number of nines to begin with, but that aside, writing this:
.999...
does not actually represent an ongoing process of writing an infinite number of nines.
The case *is* closed. .999 repeating equals 1. The *number* "0.999..." does not represent a process. It represents a number, and that number is 1. You can write "1" as 1, or you can write "1" as ".999...". Two different representations of the same number.
Saying that ".999..." doesn't equal 1 is like saying that 3/2 doesn't equal 1.5 because the 3 hasn't been divided into 2 yet ...
Look at it this way:
1 - (any nonexistent number) = 1
There is no real number between .999 repeating and 1.
(make sure you watch the entire second video if you are going to use it in an argument)
https://en.wikipedia.org/wiki/0.999.
https://files.eric.ed.gov/fulltext/EJ961516.pdf
9×∑k=1∞10−k:=9limn→∞×∑k=1n10−k=9×(110+1100+11000+…)
https://www.themathdoctors.org/frequently-questioned-answers-0-999-1/
http://backreaction.blogspot.com/2009/05/is-1-0999999.html
https://polymathematics.typepad.com/polymath/2006/06/no_im_sorry_it_.html
I'm not sure why you pointed me to these videos. But the girl in the 2nd one totally agrees with me and not you.
Did you even watch the video??
THANKS Though ;-)
Nope! I won.
Math is not a democracy. It doesn't matter how many idiots vote in something it still does not make it legit.
Since you're talking about a bunch of people with degrees who are all better at math then you are, I think you've lost this point. If you can refute anything, and not just say "it never reaches 1" ad infinitum, or come up with some new argument, great...if not, we can just cycle to some new posters that might know how to prove a point better.