If (a/b)+(c/d)
will equal ((da+bc))/(bd)
Then
(1/infinity)+(1/infinity) shall equal ((infinity*1)+(infinity*1))/(infinity)
Which when simplified is infinity/infinity, which is indeterminate.
can't really argue with that
generally, just don't do arithmetic with infinity
(i/1)+(1/infinity) will equal
(Infinity i+1+infinity)/infinity
Rather illogical.
If (a/b)+(c/d)
will equal ((da+bc))/(bd)
Then
(1/infinity)+(1/infinity) shall equal ((infinity*1)+(infinity*1))/(infinity)
Which when simplified is infinity/infinity, which is indeterminate.