e^ix^2=cos(x^2)+isin(x^2)
(e^ix)^x=cos(x^2)+isin(x^2)
(cos(x)+isin(x))^x=cos(x^2)+isin(x^2)
However, I cannot simplify the left side...
e^ix^2=cos(x^2)+isin(x^2)
(e^ix)^x=cos(x^2)+isin(x^2)
(cos(x)+isin(x))^x=cos(x^2)+isin(x^2)
However, I cannot simplify the left side...
Hi brother just watched ur profile really great content can you please say do you copy those or your own decoration.if ur own your a future mark Twain for sure.thanks.i think they were copied right .
Hi brother just watched ur profile really great content can you please say do you copy those or your own decoration.if ur own your a future mark Twain for sure.thanks.i think they were copied right .
One quote is Blaise pascal but the rest are me I think... I haven’t read my own profile recently lol
Sometimes using its equivalence series would help. Such as binomial series, etc.
The result would not exact but pretty close approximating.
I don't think I like representing with Taylor Series though...
There are many kinds of the series you can choose to suit your purpose.
The result would not exact but satisfying for technical application purposes. Even the series are used to solve the problem in mathematical field.
Is it?!