Make the equation so that the terms with x are on one side and then just divide by the number multiplied by x.
For example an easier equation:
50 times x - 10 = 90
50 times x = 100
(50)(x) = 100
(50)(x)/50 = 100/50
x = 2
Sorry if that's confusing I'm not math tutor xD
If there is a number divided or multiplied by x and gives you a number bring the number to the other side and do the calculation
For example
76+x=100
so as 76 is a positive no ,when you bring it to the other side it changes to negative
like this
x=100-76
therefore x=24
Hope it helped 
You do the same with fractions and decimals
Which grade are you anyway ?
Uh oh, I got a different answer! 
I’ve not done these problems in years, so hopefully this helps.
Finding x will be easy for you
Just frame the equation properly and you will get the answer
Uh oh, I got a different answer!
I’ve not done these problems in years, so hopefully this helps.
How'd you get 50 in the second equation?
Um, how did you get 90 in the first place
It was just an example I made up xD
Uh oh, I got a different answer!
I’ve not done these problems in years, so hopefully this helps.
How'd you get 50 in the second equation?
I just plugged in my answer to see if I got the correct result (50). Take my answer with a grain of salt though, I’ve not done these in a long time.
Here’s a better explanation than mine:
100/(5/3 x)=50
50(5/3 x)=100
(250/3)x=100
x=100/(250/3)
x=300/250=6/5
100/(5/3 x)=50
50(5/3 x)=100
(250/3)x=100
x=100/(250/3)
x=300/250=6/5
How'd u get 50???
Uh oh, I got a different answer!
I’ve not done these problems in years, so hopefully this helps.
You made an mistake when you flipped the fraction. (5/3)x is 5x/3 so flipped would be 3/(5x) not (3/5)x
Try to seperate the X on one side and the numbers on another side
How to find x in this sort of division problem example
100 divided by ( 1 2/3 times x) = 50.
Just an example not sure if it is a good example or not though. How to find x? These problems are tripping me up