Bump.
I will accept all friend requests

If you can in detail explain your pfp I will send one
The nine-point circle of a triangle ABC is a circle that passes through the midpoint of AB, the midpoint of AC, the midpoint of BC, the foot of perpendicular from A to BC, the foot of perpendicular from B to AC, the foot of perpendicular from C to AB, the midpoint of the line segment joining A and the orthocenter of ABC, the midpoint of the line segment joining B and the orthocenter of ABC and the midpoint of the line segment joining C and the orthocenter of ABC.

If you can in detail explain your pfp I will send one
The nine-point circle of a triangle ABC is a circle that passes through the midpoint of AB, the midpoint of AC, the midpoint of BC, the foot of perpendicular from A to BC, the foot of perpendicular from B to AC, the foot of perpendicular from C to AB, the midpoint of the line segment joining A and the orthocenter of ABC, the midpoint of the line segment joining B and the orthocenter of ABC and the midpoint of the line segment joining C and the orthocenter of ABC.
I am a man of my word
My goal is to reach 100 friends in order to get the Social Butterfly achievement. Currently, I have 78 friends. Feel free to send me a friend request - I'll accept all of them. (This is the original post: https://www.chess.com/forum/view/off-topic/i-will-accept-all-friend-requests) (I cannot comment in the post because I have written 5 consecutive comments.) (Also, please read the blog mentioned in the original post because I want to get the Good Read achievement by obtaining 100 views.) (Also, please join my club (Daily Variants) which was also mentioned in the original post. Anyone who sends me a friend request will receive an e-book of chess puzzles. Anyone who is kind enough to give me a 1-month gold membership will receive all 109 cheers awards, the e-book and 37 chess videos.