Demonstrating as well that (0^0) is equivalent to (♾️^0)
If (x^0)=3
Nope, it works. Friend.
You are acting deliberately S*upid.
If you could perform the operations that you have, then you can surmise that When x is 0, then x/x will equal 0/0 - Equals any Number.
You are acting deliberately S*upid.
If you could perform thise operations then you can surmise that When x is 0, then x/x will equal 0/0 - Equals any Number.
0/0 = undefined
You are acting deliberately S*upid.
If you could perform thise operations then you can surmise that When x is 0, then x/x will equal 0/0 - Equals any Number.
0/0 = undefined
That's not what you stated earlier, here.
You are acting deliberately S*upid.
If you could perform thise operations then you can surmise that When x is 0, then x/x will equal 0/0 - Equals any Number.
0/0 = undefined
That's not what you stated earlier, here.
0/0 is an exception
stop making idiotic posts please
x^1 = x
x^0 = x/x = 1...
See.
You were arguing with my thesis, that x must be 0 or infinity.
Then x^1 will equal 3x.
So x therefore would equal 0 or ♾️.
Showing that (0^0) can equal 3, and not only 1.