it the power of -1 so it can't exist
What is, 0^-1?
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Then what is, (1)^-1??
Well, Sir
You haven't disproven or properly questioned my theorem, that 0^-1 is x/0 For any non 0, x.
CoolRichFordLover wrote:
its 1
Yep, that's true.
Because 0/x is 0, for any non 0 x.
0^-1 is x/0, for any non 0, x.