What is The Square Root of "Infinity i?"

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√(ni)= a+bi ni = a²+2abi-b² a²=b² 2ab = n a=±b Both a and b are positive because we took the square root. a=b a = √(2n) When n = ∞ a = b = ∞ So √(∞i) = ∞+∞i By some definitions of √(ni)

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Wouldn’t it just be infinity
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Or else the problem is not possible because infinity cannot be defined in terms of numbers
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Bump!

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" So √(∞i) = ∞+∞i By some definitions of √(ni)"

Nope

(infinity+infinity i) (infinity+infinity i) is

Infinity+infinity i+infinity -infinity is infinity+infinity i.

Why did you post this??

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MeaslyTurtle56 wrote:
Or else the problem is not possible because infinity cannot be defined in terms of numbers

What is infinity+infinity i then?

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