Pos #2 is quite possible
Is this position legal?

Added a new one.
Not so obvious, but it is possible. The tricky part is that there is a way to "lose a tempo" depending on where you capture the first black knight.

This is the next position
Not legal.
Fifteen captures are needed from each side to form this position. Since among those 15, there are pawns, it cannot be possible, since white still has most of his pawns.

This is the next position
Not legal.
Fifteen captures are needed from each side to form this position. Since among those 15, there are pawns, it cannot be possible, since white still has most of his pawns.
Only 10 captures from each side, as the pawn piles are on relatively central files.
There is probably still a problem with crossing of pawns, but it is not obvious whether it is legal or not.

#30: each side has made at least 9 captures. 18 captures + 2 kings and six pawns equals 32. The situation can be created, hence is it a legal position.

This is the next position
Not legal.
Fifteen captures are needed from each side to form this position. Since among those 15, there are pawns, it cannot be possible, since white still has most of his pawns.
Only 10 captures from each side, as the pawn piles are on relatively central files.
There is probably still a problem with crossing of pawns, but it is not obvious whether it is legal or not.
How is it ten? The white pawn on f7 must have started from a2, so 5 captures are needed to get there. The pawn on f7 must have originated from b2, so 4 captures are needed. There is a pattern here. So, we can use y=1+2+3+4+5 to find that that we need 15 captures on each side to form this position. For the two pawns in the middle of the stack, it doesn't matter where they originated from; the number is still the same.

1... fxe6 2... exd5 3... dxc4 4... c3 5... c2 6... exd6 7... dxc5 8... c4 9... c3 10... axb6 11... bxc5 12... c4 13... bxc6 14... c5 15... dxc6 and you have all pawns on the c-file. If you count the number of captures, then will you see that there are nine captures.

This is the next position
Not legal.
Fifteen captures are needed from each side to form this position. Since among those 15, there are pawns, it cannot be possible, since white still has most of his pawns.
Only 10 captures from each side, as the pawn piles are on relatively central files.
There is probably still a problem with crossing of pawns, but it is not obvious whether it is legal or not.
How is it ten? The white pawn on f7 must have started from a2, so 5 captures are needed to get there. The pawn on f7 must have originated from b2, so 4 captures are needed. There is a pattern here. So, we can use y=1+2+3+4+5 to find that that we need 15 captures on each side to form this position. For the two pawns in the middle of the stack, it doesn't matter where they originated from; the number is still the same.
Pawns can move forward, so you don't need the a-pawn. You can use the h and g-pawns. But you'll still need 9 captures, which is not possible, since youll only have 7 pieces and 2 pawns. But the white a-pawn will never allow a black pawn to go towards the c-file. The b-pawn can be used as food for the a-pawn. The position is per definition not legal.

Not legal. The white pawns are all on the f file, so at least 9 captures are necessary - 1 each for the e and g pawns, 2 for the d and h pawns and 3 for the c pawn. Now black has lost 9 pieces - all except the 6 pawns and his king - so you might think that the position is possible. BUT: one of the captured black pieces must be the black h pawn, and white has no spare captures to either take this or to use it on the way to the illustrated position. Therefore white needs more than 9 captures, which is does not have and, obviously, the same logic applies to the black pawns. So the position is not legal.
Edit - having seen the solution, I overlooked promotions, so I was wrong! :)
Added a new one.