emmm, eat the pawn by Queen then come Role the knight 
Mate in 2 white to play...
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a1 square is bottom left, the black King is on...
Killer_Mirage wrote:
emmm, eat the pawn by Queen then come Role the knight
well, the bishop would eat the knight...
whatttttt, but. . . .. .but 
Qb4, no matter the response from black white wins next move
Killer_Mirage wrote:
whatttttt, but. . . .. .but
lol, guess again...
Tough one. I'm a terrible visualizer when I can't move the pieces on an analysis boad (anyone want to play me OTB?), but I think the answer is Qc2. Black either responds with with Rc3 to prevent Qb2, in which case Qxc3#, or black responds with Bxc2, to which white answers Nxc2#.
JasonSchlotter wrote:
Tough one. I'm a terrible visualizer when I can't move the pieces on an analysis boad (anyone want to play me OTB?), but I think the answer is Qc2. Black either responds with with Rc3 to prevent Qb2, in which case Qxc3#, or black responds with Bxc2, to which white answers Nxc2#.
Qc2= Bxc2...
JasonSchlotter wrote:
Tough one. I'm a terrible visualizer when I can't move the pieces on an analysis boad (anyone want to play me OTB?), but I think the answer is Qc2. Black either responds with with Rc3 to prevent Qb2, in which case Qxc3#, or black responds with Bxc2, to which white answers Nxc2#.
Black can respond with ..Rb3 to prevent Qb2 and it's not mate in two.
With Qb4:
If ..Bb3, Qc3#
If ..Rb3, Nc2#
If ..Rc3+, Qxc3#
PooTeeWeet wrote:
Qb4, no matter the response from black white wins next move
Qb4 also seems to look ok. Multiple solutions?
veteranmate wrote:
JasonSchlotter wrote:
Tough one. I'm a terrible visualizer when I can't move the pieces on an analysis boad (anyone want to play me OTB?), but I think the answer is Qc2. Black either responds with with Rc3 to prevent Qb2, in which case Qxc3#, or black responds with Bxc2, to which white answers Nxc2#.
Qc2= Bxc2...
But doesn't mean Bxc2 will happen. Qc2, Rb3...
veteranmate wrote:
JasonSchlotter wrote:
Tough one. I'm a terrible visualizer when I can't move the pieces on an analysis boad (anyone want to play me OTB?), but I think the answer is Qc2. Black either responds with with Rc3 to prevent Qb2, in which case Qxc3#, or black responds with Bxc2, to which white answers Nxc2#.
Qc2= Bxc2...
Which could be met with Nxc2#. But Qc2 doesn't guarantee a mate in 2
veteranmate wrote:
JasonSchlotter wrote:
Tough one. I'm a terrible visualizer when I can't move the pieces on an analysis boad (anyone want to play me OTB?), but I think the answer is Qc2. Black either responds with with Rc3 to prevent Qb2, in which case Qxc3#, or black responds with Bxc2, to which white answers Nxc2#.
Qc2= Bxc2...
And after Bxc2 you have Nxc2#.
However, PooTooTweet is correct as Qb4 is the only way to mate in 2.
PooTeeWeet wrote:
JasonSchlotter wrote:
Tough one. I'm a terrible visualizer when I can't move the pieces on an analysis boad (anyone want to play me OTB?), but I think the answer is Qc2. Black either responds with with Rc3 to prevent Qb2, in which case Qxc3#, or black responds with Bxc2, to which white answers Nxc2#.
Black can respond with ..Rb3 to prevent Qb2 and it's not mate in two.
With Qb4:
If ..Bb3, Qc3#
If ..Rb3, Nc2#
If ..Rc3+, Qxc3#
[COMMENT DELETED]
Queen takes bishop, rook takes queen, knight to b3 mate
White is at bottom...