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IMPORTANT UPDATE
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penguingm1 wrote:
Report 5random for language
hahaha bruh u curse every second :(
lol you do know you can easily be reported on ICC haha..but yah
drawmaster snail is such a noob. although i cant talk really cuz i am sort of drawish also...
all of you are
dood i don't think i've drawn a tournament game in two months.
who are u Bangalore2? And PENGUINGM1=Clubpenguin+CardJitsu-black belt (cos maxed out)(sin 24/7)
Hi snail.
I thought some one said IMPORTANT update!!
solve this easy as **** math problem. If you can't, you are dumb.
1/1 + 2/2 + 3/4 + 4/8 + 5/16 + 6/32 + 7/64 + 8/128 + 9/256... It goes on infinitely. Find the sum.
Apr 20, 2015
0
#37
The equation for that sum is n/(2^(n-1)).
According to the limit ratio test, the series will converge if the limit as n approaches infinity of the absolute value of (a of n+1)/(a of n) is less than one.
((n+1)/(2^n)) x ((2^(n-1))/(n) = (n+1)/(2n) which approaches 1/2 as n approaches infinity. Therefore, the series does converge.
However, since it is not a geometric series, it is not possible to use calculus to determine what value it converges to.
Therefore your question is a trick question and cannot be answered, unless the answer can be determined using methods above Calculus BC level.
Apr 20, 2015
0
#39
No it cannot. I am taking calculus and we are working on summations right now. When you get to Calc BC, you'll understand.
gents? which gents?