black has 13 pieces on board.
white requires 3 captures for the doubled pawns
the pawn a6
I hope this position will be a little more challenging. It was submitted as a helpmate in 10 problem (Evgen S. Orlov, 5516 The Ural's Problemist 60 2009). Why is it illegal?
It is illegal because Black's g-pawn couldn't get over the the right!!!!
I hope this position will be a little more challenging. It was submitted as a helpmate in 10 problem (Evgen S. Orlov, 5516 The Ural's Problemist 60 2009). Why is it illegal?
It is illegal because Black's g-pawn couldn't get over the the right!!!!
Also illegal because the coordinates are wrong, because h1 is a dark square, and a1 is a light square! (I just looked at a normal board)
Okay, I have an idea. I know by counting the White pieces that Black captured 7 times (that includes the captures that happen in the process of trading). Let's see if the pawns can capture enough times to reach the positions they are at in the position shown. I'm counting...
Now you are on the right track.
this is a legal position
Yes, easily legal. But we want to see illegal positions that look like they could be legal.
watch:
If you'd like to see it done in 20 moves instead of 29, here it is.
white to move
thats legal
The other solution, in the next post after the problem was posted, used the bishop instead of the queen to lose a move. Both work equally well.
and this is legal as white to move. nobody ever said black had to be able to castle.
I'm not sure what the point of this one is. Your final position is the same as the position you had after move 1.
#4729 or # 4788, from n9531l1 : It is illegal because: 1. Remaining white pawns have performed at least three captures to reach their current positions. [e.g. fxg, bxc, exd] This is legal for their are three black pieces missing 2. The seven black pawns from c-file up to h-file must have done at least seven captures of white pieces. This is legal as well, for their are seven white pieces missing [ e.g. gxh, fxg exf, dxexf, bxc, cxd ] So, all captured white pieces must have been taken by black pawns! 3. But one of these seven white pieces is a white pawn, and in case of the white a-pawn, then it was captured by a black b-pawn. But the black b-pawn captured to the c-file [see 2.], so the black a-pawn needed to capture an white piece number eight to reach the b-file first. But there are still nine white pieces... If it wasn't the white a-pawn which has been captured among the seven black captures, the white a-pawn has moved to the c-file by two captures, which totals then to at least four black pieces captured by white. But there are still thirteen black pieces .... So the position is illegal. But probably there is shorter argumentation?
Here's a repeat of my #4729 position from five days ago. I'm surprised nobody has posted a valid explanation of why it's illegal. It's not too difficult.