MATH questions
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No one wants the sum of natural numbers huh? Ok.
so what is this post about again? do we post a question?
Please be relevant, helpful & nice!
sorry i read the wrong page. 2/3????????
No 0.9999... is different from 1.
Poolala wrote:
x = 0.999...
10x = 9.999...
10x - x = 9.999... - 0.999...
9x = 9
x = 1
(Taken from the wikipedia article for 0.999...)
The step from 3 to 4 assumes 0.000...01=0.
But assuming this makes 0.99..=1 trivial by simply subtracting each side from 1.
So all this "proof" really does is attempt to hide the 0.00..01=0 assumption.
Given that a confluent hypergeometric function (of matrix argument) exists and is equal to a complete spherical surface integral in R^n, is there an expression for the partial surface integral?
please_let_me_win wrote:
(Similar type of problem but x=0.999... and 10x=10.999... doesn't work for obvious reasons)
1) Prove that 2.131313 (repeating decimal) is a rational number.
Let x = 2.131313 (repeating decimal).
100x = 213.131313 (repeating decimal)
Subtracting,
99x = 213 - 2 = 211
x = 211/99 which is a rational number (as it can be expressed in fractional form)
2) Prove that log23is irrational.
Let,
So,
2 raised to any power is always an even number, and
3 raised to any power is always an odd number.
Therefore, will never be satisfied and m/n will never be a rational number. This means log23 is irrational.
for 1)
100x-x=99x
213.131313 - 2.1313 = 211.000013
211.000013/99 is not rational.
You mean, sometimes wikipedia is right...???
waffllemaster wrote:
No one wants the sum of natural numbers huh? Ok.
I do! By any chance could it be -1/12? :P
Feb 5, 2014
0
#32
x=k(∂x/∂y)
Solve for x, assuming k is a constant
Because nobody likes partial derivatives.
"Repeating" is non-rigorous.
Otomun wrote:
What does .000...01 even mean?
As close to 0 as possible without reaching zero.
Feb 5, 2014
0
#36
A real number doesn't "approach" or "get close to" a value. It doesn't "move" on the number line; it sits at one spot.
Otomun wrote:
A real number doesn't "approach" or "get close to" a value. It doesn't "move" on the number line; it sits at one spot.
In that case 0.999.. is meaningless in the real number system.
Nope. 0.999... = 1. It is 1. It is another way of writing 1, just as 2-1 or 5/5 are. They all sit at 1; they all are 1.
0.0000...1 on the other hand is not just meaningless, it is impossible to define. The "..." means an infinite number of zeroes. Infinite. Zeroes which never end. There is no last 1, because there is no last zero for it to go after.
