58 Qh1 and its all over for Black, neither of the pawns will be able to promote.
2 pawns trump a queen??
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He also should have played a4 instead of Kxb5
It is 11 years old, but it's an interesting end position. Of course, 64. Kd4?? allows e1=Q!! and white will eventually lose. Even if white had played 64. Qd2 (correct), black can still hold the draw:
64. Qd2! Kg2! 65. Qe1 f2! 66. Qxe2 Kg1! and white's king is too far away to win.
These kinds of pawn races are very common, so it's important to know how to win the game after you win the race.
For the most part, only the lead pawn matters, so both 58. Qh1 and 58. Qa1 win trivially, and even 58. Qe8 is good enough to win. On the next move, the only winning move left was 59. Qa3+!, i.e. ..Kf2 60. Qc5+ Kg2 61. Qe5 Kf2 62. Qxf5+ and wins. It's essential for the f-pawn to fall with check, but the winning procedure against a central pawn on the 7th rank is well known from there (force the defending king in front of the pawn, then approach with your own).
I just finished a game, and somehow, even though my opponent won the pawn promotion race with his only pawn, with my king and 2 pawns working together, I managed to get into position to promote, then my opponent blundered to allow the promotion and immediately resigned. So I'm wondering, what should my opponent have done to prevent this? So here's the game, feel free to post about any other parts of the game.