blueemu wrote:
paper_llama wrote:
1.Rd8 Bd5
2.Be4 Bb7
3.Rf8
Take it.
Ok, now I see.
1.Rd8 Bd5
2.Be4 Bb7
3.Rf8 Bxe4
4.Rf3
And of course black doesn't have to capture the rook... hard to get my brain into losing mode heh.
Completely forced checkmates
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Apr 19, 2023
0
#43
So the rook can't be on the same file as the bishop and can't go "behind" it (until Rh8 wins).
If it goes on same file or less, then black can capture and there is no forced mate. When the rook is in front (or on h8) then capturing the bishop results in checkmate. That's the initial logic of the puzzle.
Apr 19, 2023
0
#44
Think of it as an "opposition" or "triangulation" problem. The question of White or Black to move is critical. EVERY POSITION that is winning for White is only drawing instead if the wrong side is on the move.
Apr 19, 2023
0
#45
blueemu wrote:
Think of it as an "opposition" or "triangulation" problem. The question of White or Black to move is critical. EVERY POSITION that is winning for White is only drawing instead if the wrong side is on the move.
Sure, like corresponding squares. Using your numbers I could solve the puzzle, but I didn't understand it until I found out why the incorrect moves don't work.
I still think white can force a mate with my sequence of moves, just maybe not as fast or something.
That turns out NOT to be the case.
Your proposed line "loses the opposition", so to speak.