I need a math genius to explain how many Chess positions there are.

1x64=24+4+36 36x55+4x60+24x58=3612

3612 is the number of positions possible with just 2 kings

3612x62x61=13660584

13660584 is the number of positions with 2 queens and 2 kings

There's at least 4

WHAT HAPPENS IN THE CHURCH STAYS IN TE CHURCH

this was the best my online calculator could handle so this is my solution to the number of positions in chess

1022134645914424867528704000⋅1026043200⋅4680030820902586690712371200

1022134645914424867528704000 times 1026043200 times 4680030820902586690712371200

" Enjoy Chess Many Possibilities " - Samanthnaidu

The upper bound that I can calculate is 5.58×10⁵² positions.

The number of both king positions on the board is (4×60)+(24×58)+(36×55) = 3,612.

The number of ways to place 15 white pieces into the remaining 62 squares is less than C(62, 15)×6¹⁵.

The number of ways to place 15 black pieces into the remaining 47 squares is less than C(47, 15)×6¹⁵.

So we have upper bound 3,612 × (C(62, 15)×6¹⁵) × (C(47, 15)×6¹⁵) or about 5.58×10⁵² positions. This number includes pawn promotions and many illegal positions.

For a more detailed proof, check out this blog.

https://www.chess.com/blog/jomsup/math-proves-upper-bound-for-the-number-of-chess-positions

I read this, but it includes only legal positions:

Possible Positions: 10^43 to 10^50

Also this:

Possible games (move sequences): around 10^120

I don't know