Alexander's nickname is Benjamin Button 
Solve this Riddle if you can
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You can if one of the services runs in under all the houses.
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May 16, 2013
0
#85
winerkleiner wrote:
learningthemoves wrote:
Coolbluesky wrote:
Alexander is 20 years old in 1980, but only 15 years old in 1985. How is this possible?
Alexander is the surname of two brothers born ten years apart.
John Alexander was born in 1960 and was 20 years old in 1980.
His brother Peter Alexander was born in 1970 and of course was 15 years old in 1985.
The reason I know it's possible is because my family has known the Alexander family for years. I'm glad you asked because it reminded me they still owe us some money from the late 90s. If you disagree, try to deny it or suggest some other answer instead, that means you are trying to cover up for them and thereby agree to repay their debt to me in their stead which is okay too.
Lol, nice!
Thank you for your moral support in this sensitive matter. We trust the defaulting party/poster will finally bring this to resolution and clear the Alexander name from the embarrassing situation they created for their family. $200M is no drop in the bucket, but we are glad Coolbluesky has shown by her interest in posting on the matter her assumed duty to repay in full and all shall be well.
May 16, 2013
0
#86
Assoluto wrote:
I'll give everyone a example: Can you finishing connecting these lines without touching eachother? It's much harder than it seems...
Why would we struggle not to touch each other just to finish connecting the lines? Creepiness.
May 16, 2013
0
#87
Sigh. Nobody here heard of Kuratowski's theorem? That puzzle about utilities is asking you to disprove half of it. Cannot be done.
Except the house on the left has two red and no blue and the house on the right has two blue and no red.
May 16, 2013
0
#89
Wrong. There are two connections A-W, none A-O, two O-C, and none W-C.
Solution is not possible.
May 16, 2013
0
#91
Assoluto wrote:
That's right, it's because it's impossible.
Which is exactly what I wrote ("cannot be done") just before you posted that bogosity in comment #114.
Assoluto wrote:
That's right, it's because it's impossible. That's the closest solution there is.
This seems closer. I took one of A's extraneous red lines and gave it to C.
Assoluto and RubiksRevenge got it right. It's B.C.
May 16, 2013
0
#94
Google Euler's work on planar graphs. By the way, I think I solved the " I am all colors of the rainbow and eat an endless number of sheep" riddle from earlier in the thread: tie-dyed wolves.
The first guy could do a quick count of the remaining 99 hats and work out which colors have even number and therefore which have odd number. He could have arranged with everyone else in the group to call out the color that represents the odd hats he sees. The 2nd person will then know what hat he wears by seeing if there is still an odd number left of that color. If answer is yes then 2 person must be wearing the opposite color.The players keep track of the colors called out and know what to say when it is their turn by using the odd or even method.
Xilmi wrote:
My favourite riddle is this one:
There is a dictator, who controls a very small country with a population of 100 people. One day, he decides to test if his country is intelligent so he goes to them and says "Tomorrow, I will line you up single file so that the person in the back can see everyone else, and the person in the front can see no one. I will then place a hat on each of your heads, either red or blue (the specific colors are irrelevent, you may request a different set of colors, and the distribution of the hats can be anything, 50/50, 83 red, 17 blue, or any combination of hats to make one hundred). Nobody will be allowed to talk or move unless I speak to them first, at which point they may only say one word and that word can either be blue or red, anything more and everyone dies. I will go to the person in the back, I will ask him what color hat he has, and I will begin a timer set for five minutes. At the end of this timer he must immediately say either "red" or "blue". If he answers correctly, he will live, if not, he will be shot in the head, so everybody knows he was wrong. I will proceed up the line asking each person. If you are intelligent enough, you will come up with a strategy to save at least 99 of the people in your town, If not, too bad. good luck." There are no bullshit answers like hold up a mirror, and they cannot see their own hats, there is a real answers.
I thought about it several days and found the solution by coincidence while taking a dump. I had yet to check if the solution actually works after that and was very proud of myself for having solved it.
Another impossible one here. Can you cross all 7 bridges without going over the same one twice? (no swimming or going around the river allowed.)
There is a flea in the middle of a circle. The radius of the circle is 10 meters. The flea can jump 5 meters, but after that it will be tired and can only jump 2.5m on its next jump. Each time it jumps the distance it can travel halves. How many jumps will it take for the flea to leave the circle? (assume that the flea occupies no space or that all the distances are measured from it's exact centre.)
May 17, 2013
0
#98
Holy shit! Just do some homework. Start with Euler. These problems are antiques and have been definitively solved a very long time ago. By all means enjoy the wonderful elegance of the solutions instead of wasting all this time.
odyson wrote:
Holy shit! Just do some homework. Start with Euler. These problems are antiques and have been definitively solved a very long time ago. By all means enjoy the wonderful elegance of the solutions instead of wasting all this time.
It was Euler who proved that the 7 bridges problem has no solution. That's why I mentioned it. The flea problem is ancient too.
Alexander is 20 years old in 1980, but only 15 years old in 1985. How is this possible?
Alexander is the surname of two brothers born ten years apart.
John Alexander was born in 1960 and was 20 years old in 1980.
His brother Peter Alexander was born in 1970 and of course was 15 years old in 1985.
The reason I know it's possible is because my family has known the Alexander family for years. I'm glad you asked because it reminded me they still owe us some money from the late 90s. If you disagree, try to deny it or suggest some other answer instead, that means you are trying to cover up for them and thereby agree to repay their debt to me in their stead which is okay too.
Lol, nice!