A very hard mate in 1!! - Chess Forums - Page 2

szammie

Dec 21, 2012

0

#21

If there is a mate n 1: I don't see it; but still looking.

SZ.

Adriandmen

Dec 21, 2012

0

#22

makikihustle schreef:

I don't see mate in one. Mate in one means the next move is checkmate.

That means the next move has to be a check that the black king cannot escape from. There are only five possible checks in the diagram:

1) BxB. Not mate. Black can recapture with the pawn.

2) Rxp. Not mate. Black can recapture with the pawn.

3) Qxp. Not mate. Black can recapture with the pawn.

4) Qd4+. Not mate. Black can recapture with c5 pawn.

5) Nc3+. Not mate. Black can recapture with the pawn.

No other possible checks.. So no possible mate in one. Unless there's an invisible piece somewhere that I'm not seeing. :D

Qxe5+ (or Rxe5+) is a fun mate in two, though!

Yes, great thinking!!. Now you know there is a problem with the diagram. Just figure out what it is .

Adriandmen

Dec 21, 2012

0

#23

Bicarbonatofsoda schreef:

1.....Bc8

just put that bishop back where it belongs

You cannot put the bishop away, because black would be in check. But you are getting there!!

EricFleet

Dec 21, 2012

0

#24

I think when we get the answer, it will turn out to be something like this

Frankwho

Dec 21, 2012

0

#25

Get rid of the d3 pawn(to make the position legal)and play Qd1.

makikihustle

Dec 21, 2012

0

#26

EricFleet wrote:

I think when we get the answer, it will turn out to be something like this

Lol! :D

Adriandmen

Dec 21, 2012

0

#27

Frankwho schreef:

Get rid of the d3 pawn(to make the position legal)and play Qd1.

You got the answer!!!. The position is illegal, because the bishop on e6 has to be a promoted piece. So, you have to get rid of one of the pawns... Removing a pawn, doesn't matter which one if you just don't leave black in check, will lead to mate:

Remove:

BPawn b4 - Nc3#
BPawn c5 - Qd5#
BPawn b7 - Qa8#
BPawn d7 - Bxe6#
BPawn f3 - Qh1#
BPawn d3 - Qd1#
BPawn d6 - Rxe5# / Qxe5#

EricFleet

Dec 21, 2012

0

#28

I was right with both of my posts.

eddysallin

Dec 21, 2012

0

#29

Can u find a mate in 1? The ANSWER ? is"NO"----i cannot find a mate in one! A play on words, not a chess puzzle answer

makikihustle

Dec 21, 2012

0

#30

That's like saying, "Can you find the two positive whole numbers that add up to 3? But one of numbers is not a 2!"

And when people are stumped, you say "The correct answer is 2+2=4! Haha!"

*slaps forehead*

LizardMasteredChess1

Dec 21, 2012

0

#31

I don't see checkmate in one.

waffllemaster

Dec 21, 2012

0

#32

b5-c4. White takes back 1 move and it's mate :p

LizardMasteredChess1

Feb 11, 2013

0

#33

Pawn f4 is not supposed to be there. You would move Nf4.

dickv

Feb 11, 2013

0

#34

[COMMENT DELETED]

sisu

Feb 12, 2013

0

#35

Let's make it happen!

learningthemoves

Feb 12, 2013

0

#36

Nevermind. lol.

eddysallin

Feb 12, 2013

0

#37

PantaRhei wrote:

Adriandmen wrote:

Frankwho schreef:

Get rid of the d3 pawn(to make the position legal)and play Qd1.

You got the answer!!!. The position is illegal, because the bishop on e6 has to be a promoted piece. So, you have to get rid of one of the pawns... Removing a pawn, doesn't matter which one if you just don't leave black in check, will lead to mate:

Remove:

BPawn b4 - Nc3# BPawn c5 - Qd5# BPawn b7 - Qa8# BPawn d7 - Bxe6# BPawn f3 - Qh1# BPawn d3 - Qd1# BPawn d6 - Rxe5# / Qxe5#

My opinion on the only legal answer:

I may be wrong, but i will share my opinion with you for criticism. I think that if you wish to achieve a legal position by removing only one black pawn your only option is to remove the d3 pawn.

The number of minimum lateral displacements of the black pawns are 8. That means that black has captured at least 8 white pieces, inducing a contradiction because the number of white pieces is more than 8 (12). If you wish to remove one pawn to make the position legal then you must remove a pawn that has made a minimum of 4 lateral displacements to make the position legal, because only that will eliminate the contradiction (with that pawn elimination now 12 white pieces can be on the board).

The only pawn that can have made 4 lateral displacements is the pawn on d3 if you assume it is an h pawn.

Notice that no other pawn can have made 4 or more lateral displacements.

Therefore, the only valid answer to the problem if you have the condition that you can only remove one black pawn is to remove the d3 pawn.

You shouldn't include the other answers.

If i am wrong i would really like to hear good criticism. This problem is interesting.

Thanks for the problem.

To create an illegal position and then say"mate in 1" is really, really stupid. Puzzles are established for chess entertainment......not mind reading.

EvenDeeperBlue

Feb 12, 2013

0

#38

Perhaps we could suggest to chess.com that they call one of their puzzles of the day "Mate in 1" when it is really (say) a mate in 3. That would at least reduce the number of "easy" comments...

EthanKohn

Dec 15, 2016

0

#39

It's a trick question black bishop f5

ArgoNavis

Dec 15, 2016

0

#40

And the necrobump of the day award goes to...