Mate in 4 (incredible)

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Avatar of Aitorus

1st Problem, of Deutsche Schachbläter, 1949. Composed by Jospeh Breuer.

PoliScy discover the UNIC solution, and there is in page 2...

Avatar of anwarbd

Very hard for the BEGINNERS. But not so easy for experts also.

Avatar of Nytik

I dont think there is a mate in 4 =(. I found a mate in 6, but none for just four moves...

Edit: If anyone could, tell me the mating combination?

Avatar of RoyalFlush1991

Yeah I can't seem to find the 4 move mate either, the best I have come up with is 1. Ng5+ Kg7 2. Qxh8 Kxh8 3. f6 Kg8 4. a8=Q#, but black can avoid this mate with 1. Ng5+ Kf6 and although white has essentially guaranteed himself the win, I can't find a combination that would give him mate in 3 more moves.

Avatar of Nytik

Yes, 1. Ng5+ Kf6 ends up with the 6-move combination I have.

Avatar of Kalirren

I think I have the mate in 4.  I believe it is a queen move.

Avatar of Maradonna
Kalirren wrote:

I think I have the mate in 4.  I believe it is a queen move.


 ....don't tease me! What is your line?

I got nothing - probably a mate in about 20 or something :)

Avatar of random-d

How is it not mate after Qxh8?

Avatar of Nytik

Random-d, we are looking for CHECKmate, not STALEmate...

The term mate is never short for Stalemate, therefore I'm afraid what you've just said is wrong.

Avatar of Maradonna

'How is it not mate after Qxh8?'

There is no check with that move - or checkmate.

Avatar of Alex_M

Why is it not mate in 3?:

1. Qb8 Re8  2. Qxe8+ Kf6  3. Qe7#

Avatar of Alex_M

Wait my bad, that's not all forced. But what about this:

1. Qb8 Rxb8  2. axb8=Q Kf6  3. Qf8#

 

It's not acctually that difficult.

Avatar of Aitorus

Yes friends, there is mate in 4!!!!!

But Alex_M your solution is wrong because Rxb8 isn't forced, white can do Rg8 (For example) and there aren't mate in 4...

Avatar of maximus_dragon

i have a mate in three not forced

Avatar of Alex_M
Aitorus wrote:

Yes friends, there is mate in 4!!!!!

But Alex_M your solution is wrong because Rxb8 isn't forced, white can do Rg8 (For example) and there aren't mate in 4...


Alright, but what of this:

1. Qb8 Rg8  2. Qe5 Rxg4  3. Ng5+ Kf8  4. a8=Q#

I understand that Rxg4 isn't forced but you may substitute it with any possible rook move and you will have a mate in 4 or 3.

Avatar of caymaknight

that would be stalemate

Avatar of xMenace

1 Qb8 Rd8+ 2 Kd8 Ke6 3 Qd5+ Kf7 4 Qg7#

1 Qb8 Rg8 2 Qd5 Rd8+ 3 Kd8 Kg8 4 Qg7#

1 Qb8 Rh7 2Qe8#

1 Qb8 Rb8 2 axb8(Q) Kd6 3 Qd8#

Avatar of Alex_M
caymaknight wrote:

that would be stalemate


No. How? It is checkmate

Avatar of Alex_M
xMenace wrote:

1 Qb8 Rd8+ 2 Kd8 Ke6 3 Qd5+ Kf7 4 Qg7#

1 Qb8 Rg8 2 Qd5 Rd8+ 3 Kd8 Kg8 4 Qg7#


None of your moves make any sense. Many of them are illegal (Ex: 2... Ke6), and in others you are not taking into account the capturing of pieces (Ex: "2. Kd8" should be 2. Kxd8, the rook just moved there!)

Avatar of Aitorus

Alex_M

1. Qb8 Rg8  2. Qe5 Rxg4  3. Ng5+ Rxg5 and no mate ;)

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