Mate in 4 (incredible)

Qb8

1.Ng5 Kg7 2.Qxh8 Kxh8 3.f6 Kg8 4.a8=queen and chekmate

1.Ng5 Kf6 2.Qc6 Kxg5 3. Qg6 Mate

1.Ng5 Kf6 2.Qc6 Kg7 3.Qg6 Kf8 4.Qg7 Mate

This is the solution!

Qb8 dosen't lead to mate in 4

Big if there. It's not a forced move, and, therefore, not a correct solution. I think PolySci has figured out the one and only. Congrats!

the thing is that there are 3 possibilities, all end with checkmates, it is forced checkmate cause whatever he do, it end with mate in 4.

I don't understand why you think it's wrong.

Ive already posted the answer, you can find it on the 2nd page, it is qh1 but a8 must =r not queen, it is not mate in 4 if you promote to q

anyone saw my solution?

Ng5 does not force mate in 4

why not?

Ok, It's not wrong as far as my untrained eye can tell, but you need to add your check "+" denotations. It's very confusing without them.

after kxg5, qg6 is not mate

No, it's not. 3...Kf4. It's not a mate in 4 either. But what about his other solutions?

Master DW said: "1.Ng5 Kf6 2.Qc6 Kg7 3.Qg6 Kf8 4.Qg7 Mate"

I believe you meant 4. Qf7#. That seems to be mate...

you are right =/ I didn't see that

Yes, I meant f7

Qh1 is the only solution, so don't strain yourself looking for other options

i think alex has got it, with

1. Qb8 Rg8  2. Qe5 Rxg4  3. Ng5+ Kf8  4. a8=Q#

confusing

PoliScy have the UNIC solution, with Qb8, or Qb7 isn't mate in 4 forced....

What about these?

1. Qh1 Rxh1  2. a8=R Rh8 3. Rxh8 Kf6 4. Rf8#

1. Qh1 Kg8  2. a8=Q+  Kf7 3. Qh5+ Rxh5  4. Qf8#

Edit:oops I guess it has already been figured out.