very very tough math puzzle 2

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louie_indiana
fireballz wrote:
louie_indiana wrote:
fireballz wrote:

my first post got lost, let me try again....

when you look at the puzzle as a 3D image, by focusing into a distance, then something weird happen, you see 5 exact shapes, with numbers in them, they overlap:) perhaps I'm getting there right, friend???


i tried this... i saw a uterus.... it had no numbers in it.


did you switch the light on??


louie_indiana

no... once i discovered a uterus i figured it was better to explore around in the dark and if i saw numbers at that point i might get sidetracked away from the fun of finding a uterus.

fireballz

its definately two "7"'s, ya???

fireballz

the correct answer should be: "what question marks!"? perhaps this is an excellent explination on dark matter! do we choose to see the things we are looking for?

louie_indiana
fireballz wrote:

the correct answer should be: "what question marks!"? perhaps this is an excellent explination on dark matter! do we choose to see the things we are looking for?


"seek and ye shall find"

siddharthsbhandari

8 and 5(clockwise) certainly fit a pattern and there is no one correct answer as long as you can justify a pattern

M-Saoud

no correct answer yet

Abulabanov96

could you bother giving us the right answer yet?

PrawnEatsPrawn
Abulabanov96 wrote:

could you bother giving us the right answer yet?


I guess that he's waiting for a correct answer.

 

Harsh and old fashioned maybe, but fair.

__vxD_mAte

9 & 7

either order, because the numbers in the first wheel add up to 63, the numbers in the 2nd wheel add up to 59 and the numbers in the third could add up to 55, but at the moment they add up to 39, and 55-39 = 16 so 7 & 9.

sumedhgupte

Its 57,not 59

__vxD_mAte

Oh yes I added the 2 twice, 7 & 5 to make 12

or 8 & 4 perhaps, I am not sure anymore

__vxD_mAte

63 -6 = 57

57 -5 = 52

so 52-39 = 13

(6&7)

but not 6 and 5 and that would be a good number, and going with subtracting 6 then 7 allows the numbers 6 & 5 and that would also be good.

so subtracting 6 each time

63-6 = 57

57-6 = 51

then

51-39 = 12

so 7&5

also the non-paired numbers are missing 5 & 9, if each of the numbers are from 2 to 9, then the first circle has the numbers 7 and 4 without a pair. The second circle has the numbers 2, 3, 4, and 6 ... so what is missing from all the non-paired numbers ? Including the numbers from the third circle 8,4,2 that don't have matches.
2,3,4,6,7,8
we miss 9 & 5
Simone070792

I doubt that that solution is correct - it makes it look as though it doesn't matter where the numbers are located in the grid. I think it should matter where the numbers are located.
Though I haven't found the correct solution yet either...

__vxD_mAte

9 & 5 is already incorrect, 

so the numbers that have not been paired yet ...

2 & 4 make up pairs

PrawnEatsPrawn
__vxD_mAte wrote:

9 & 5 is already incorrect, 

so the numbers that have not been paired yet ...

2 & 4 make up pairs


 

You seem to have attempted so many solutions, that I dare to guess your approach may be called exhaustion.

__vxD_mAte
PrawnEatsPrawn wrote:
__vxD_mAte wrote:

9 & 5 is already incorrect, 

so the numbers that have not been paired yet ...

2 & 4 make up pairs


 

You seem to have attempted so many solutions, that I dare to guess your approach may be called exhaustion.


lol ... yes the answer is ... "brute force"

__vxD_mAte

I think there are mulitple dualities in the potential solutions reached from normal problem solving, the sequence of sums idea having two possible answers (8&4 or 7&5), the missing non-paired numbers vs the missing paired numbers, etc. I almost want to stare at them for a while longer but I am afraid I am bored.

jwol

2 and 4.

M-Saoud
jwol wrote:

2 and 4.


 Why ??