1/0 is a REAL problem (but not a real number)

If i is equal to the square root of -1 also known as the imaginary unit then

We know that:

a.) (i/1)+(1/0)=((i*0)+(1*1))/(1*0)=1/0

And

b.) (1/i)+(1/0)=((1*0)+(i*1))/(i*0)=i/0

The only difference in equation a.) and b.) is the addition of -i, but the result is the moving of the solution to a different complex line whose point at +infinity, and -infinity at equation a.) and imaginary +infinity, and -infinity at equation b.) all because of adding -i with 1/0 

i is not a real number either but it does not cause the "problem." 1/0 is a trouble maker and is illegal to operate with doing so is punishable.

I should clarify that as x approaches 0 from the right or "positive" side 1/x will approach 1/0, which is Infinite as a limit. And as x approaches 0 from the left or "negative" side, x will still approach 1/0, which in that case is negatively infinite as a limit.

Same applies with the imaginary plane in mathematics.

I did not include that in the OP because I thought it was theoretically demonstratable.