(1/infinity) Differs from -(1/infinity) !!

For it's true that 1/(1/infinity) is infinity

While -1/(1/infinity) is negative infinity!

1/(1/0) is less than +/-1/infinity

You're a Giant H*rd-Off!

I bet that part of your body does not function well either!?

Bump.

Yes, it is true that (1/infinity) differs from -(1/infinity). This is because infinity is not a real number, but an idea of something that has no end1. Therefore, it does not follow the usual rules of arithmetic. For example, we cannot divide by infinity, because division is defined as finding how many times one number fits into another. But infinity is not a fixed quantity, so we cannot say how many times it fits into anything. Instead, we can use limits to analyze what happens when a quantity approaches infinity or zero. Using limits, we can say that as x approaches infinity, 1/x approaches zero. This means that the value of 1/x gets closer and closer to zero, but never reaches it. Similarly, as x approaches zero, 1/x approaches infinity. This means that the value of 1/x gets larger and larger, but never reaches infinity. However, we have to be careful about the sign of x. If x is positive, then 1/x is positive, and as x approaches infinity, 1/x approaches zero from the positive side. This is written as lim(x->infinity) 1/x = 0+. If x is negative, then 1/x is negative, and as x approaches infinity, 1/x approaches zero from the negative side. This is written as lim(x->-infinity) 1/x = 0-. Similarly, if x is positive, then 1/x is positive, and as x approaches zero, 1/x approaches infinity from the positive side. This is written as lim(x->0+) 1/x = infinity. If x is negative, then 1/x is negative, and as x approaches zero, 1/x approaches infinity from the negative side. This is written as lim(x->0-) 1/x = -infinity. So, when we write 1/infinity, we are actually implying a limit, and we have to specify which direction we are approaching infinity from. If we write 1/(lim(x->infinity) x), then we mean the limit of 1/x as x approaches infinity from the positive side, which is zero. If we write 1/(lim(x->-infinity) x), then we mean the limit of 1/x as x approaches infinity from the negative side, which is also zero. But these are not the same zero, because they are approached from different directions. Therefore, 1/(lim(x->infinity) x) is not equal to 1/(lim(x->-infinity) x), even though they both look like 1/infinity. Similarly, when we write -1/infinity, we are actually implying a limit, and we have to specify which direction we are approaching infinity from. If we write -1/(lim(x->infinity) x), then we mean the limit of -1/x as x approaches infinity from the positive side, which is zero. If we write -1/(lim(x->-infinity) x), then we mean the limit of -1/x as x approaches infinity from the negative side, which is also zero. But these are not the same zero, because they are approached from different directions. Therefore, -1/(lim(x->infinity) x) is not equal to -1/(lim(x->-infinity) x), even though they both look like -1/infinity. To summarize, 1/infinity and -1/infinity are not well-defined expressions, because infinity is not a real number. We can use limits to make sense of them, but we have to specify which direction we are approaching infinity from. Depending on the direction, the limit may be zero or infinity, and the sign may be positive or negative. Therefore, 1/infinity and -1/infinity may differ depending on the context.

I use google translate to translate polish to english words