Ask Johnny Hopper Anything
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Favorite flavor of monster?
Frankenstein's
Alr
Thoughts on chimichangas?
Peskybird_flies wrote:
Thoughts on chimichangas?
When done correctly they're delicious 😋. Otherwise it's a fun word to say.
I agree. opinion on me?
rose_5525 wrote:
I agree. opinion on me?
Flower, kind and a fellow learned figure.
Thruul_Mcgon wrote:
Opinion on pneumonoultramicroscopicsilicovolcanoconiosis?
Oh my god oh my god
Thruul_Mcgon wrote:
Do you like chicken?
Only when it likes me back. I hate being a second option.
Thruul_Mcgon wrote:
#11 are you hippopotomonstrosesquipedaliophobic?
Extremely! Please exit yourself!
.
Thruul_Mcgon wrote:
.
Ottoman collapse made me cry. Thankfully it's a fairytale.
3 days ago
0
#17
Itzkrieger wrote:
Thruul_Mcgon wrote:
.
Ottoman collapse made me cry. Thankfully it's a fairytale.
FR. THE OTTOMANS NEVER COLLAPSED WE RETREATED
Make sense of this equation for quantum computing to beat any chess master
n(n+3)/2 - k(k+3)/2 = r.
You know what n is, namely 8, and
you know what r is by looking
in the box, so all you have to do
is solve this equation for k.
Multiplying by 2 and isolating
the k part gives
k(k+3) = n(n+3) - 2r.
ESSAY TITLE 1
This gives the quadratic equation
(*) k^2 + 3k -c = 0, where c =
n(n+3) - 2r.
Taking the positive solution of the
quadratic formula gives
k = (-3 + sqrt(9 + 4c))/2.
n(n+3)/2 - k(k+3)/2 = r.
You know what n is, namely 8, and
you know what r is by looking
in the box, so all you have to do
is solve this equation for k.
Multiplying by 2 and isolating
the k part gives
k(k+3) = n(n+3) - 2r.
ESSAY TITLE 1
This gives the quadratic equation
(*) k^2 + 3k -c = 0, where c =
n(n+3) - 2r.
Taking the positive solution of the
quadratic formula gives
k = (-3 + sqrt(9 + 4c))/2.
emtbiny1230 wrote:
Make sense of this equation for quantum computing to beat any chess master
n(n+3)/2 - k(k+3)/2 = r.
You know what n is, namely 8, and
you know what r is by looking
in the box, so all you have to do
is solve this equation for k.
Multiplying by 2 and isolating
the k part gives
k(k+3) = n(n+3) - 2r.
ESSAY TITLE 1
This gives the quadratic equation
(*) k^2 + 3k -c = 0, where c =
n(n+3) - 2r.
Taking the positive solution of the
quadratic formula gives
k = (-3 + sqrt(9 + 4c))/2.
n(n+3)/2 - k(k+3)/2 = r.
You know what n is, namely 8, and
you know what r is by looking
in the box, so all you have to do
is solve this equation for k.
Multiplying by 2 and isolating
the k part gives
k(k+3) = n(n+3) - 2r.
ESSAY TITLE 1
This gives the quadratic equation
(*) k^2 + 3k -c = 0, where c =
n(n+3) - 2r.
Taking the positive solution of the
quadratic formula gives
k = (-3 + sqrt(9 + 4c))/2.
Okay I've made sense of the math problems. My senses are telling me that n is 8 and... its hard?
Shoot!