DISPROVE THIS, THEN!
Sort:
Well 0 times anything is 0 right
So 0^x is automatically 0
Hmmm
One_Zeroth wrote:
If x^0=x^(1-1)=(x^1)/(x^1)
Then 0^0=0/0
If 0^0 was not Indeterminate, then the Professional Mathematicians would not have classified it as so.
"Any nonzero number raised to the power of 0."
That's true you could have stopped there.
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If x^0=x^(1-1)=(x^1)/(x^1)
Then 0^0=0/0