Further Evidence, (0^0) Is Indeterminate

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Avatar of One_Zeroith

If x^0=3 for example

Then x^1 will equal 3x, and x will therefore be 0, or infinity or -infinity

This is the outcome for any non 1 x, for x^0=y

Avatar of One_Zeroith
One_Zeroith wrote:

If x^0=3 for example

Then x^1 will equal 3x, and x will therefore be 0, or infinity or -infinity

This is the outcome for any x^0=y

That x^0=y

If, infinity^0, is indeterminate, then 0^0 will be intermediate.

Avatar of BasixWhiteBoy
Bruh no one really cares honestly
Avatar of One_Zeroith

x^0, in the case of x being 0, that would be any number.

And so, 0^0, is any number.

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