IF (1/infinity) is 0, and (1/infinity)^0 is indeterminate.

Sort:
Avatar of One_Zeroith

Then 0^(0) shall be indeterminate as well.

But as I've demonstrated before 0 does not equal 1/infinity

For one, 1/infinity is positive and 0 is not.

Avatar of One_Zeroith

You don't seem to be nearly as studious or Judicious as The Great R*bert Borkborkbork

And when one is taught what the ^ sign means. My mathematical posts are as easy to follow as 123.

Avatar of One_Zeroith
One_Zeroith wrote:

You don't seem to be nearly as studious or Judicious as The Great R*bert Borkborkbork

And when one is taught what the ^ sign means. My mathematical posts are as easy to follow as 123.

Updated.

Avatar of One_Zeroith
One_Zeroith wrote:

Then 0^(0) shall be indeterminate as well.

But as I've demonstrated before 0 does not equal 1/infinity

For one, 1/infinity is positive and 0 is not.

(1/infinity)^0 equals (1/infinity)/(1/infinity) equals infinity/infinity equals any real positive.

While 0^0 equals any positive real or negative or imaginary number, too.

So therefore, they cannot equal one another.