Is This Spam? DISPROVE THIS, THEN Pt. 2

If x^0=x^(1-1)=(x^1)/(x^1)

Then 0^0=0/0

And infinity^0=infinity/infinity 

I've shown the steps why 0^0 is 0/0. 0/0 is Indeterminate because it 0 goes into 0 no determined number of times but all.

I don't have to explain that however.

And you all bad Patzers thought that you chased me off!?

Present it more succinctly and I will.

Nope. That's never how it works.

If I talked just giggle gargle and you did not understand it, who's fault is it?

"0/0 are indeterminate forms. But just because they're both indeterminate doesn't mean they are the same or equivalent in every context.
For the second part:
The concept of infinity in mathematics is not a real number; it's an idea that represents something unbounded. As a result, operations using infinity are not straightforward.
Just like with"

"Operations using infinity are not straightforward"

Is moronic!

The "not straightforward" is not proper Mathematical language whatsoever. And is moronic.

The "other" part is not worth reading until the author properly simplifies it.

It ain't your job to simplify, but a tiny bit of effort on both parts is always welcome... or else it's just a bunch of "you! No, you!"