What is ♾️ i+1?

i being the square root of -1. Which is also called, the imaginary unit.

Let give infinity+(i) = X

Then infinity² + 2(i)(infinity) +(i)² = X²

infinity² + 2(i)(infinity) - 1 = X²

X² + 1 - infinity² = 2(i)(infinity)

X² - infinity² = 2(i)(infinity)

X⁴ - 2X²infinity² + infinity⁴ = 4(i)²(infinity)²

X⁴ - 2X²infinity² = -4infinity²-infinity⁴

X⁴ - 2X²infinity² = -infinity⁴

X⁴ - X²infinity² + infinity⁴ = 0

From X² = (-b±[b²-4ac]⁰'⁵)/2a = (-infinity²±[(-infinity)²-4(1)(infinity)⁴]⁰'⁵)/2 = (-infinity²±[-infinity⁴]⁰'⁵)/2

X² = -infinity² ± infinity²(i)

X² = -(infinity² + infinity²(i))

X² = -(infinity² + 2(infinity)((i)(infinity)) + ((i)(infinity))²

X² = -[infinity+infinity(i)]²

X = (i)infinity - (i)infinity(i)

X = infinity(i+1)

I'm not sure this method is correct or not. These numbers are far beyond my imagination.

I love theese threads

Woah

Finally!!

A thought out reply to one of my Mathematical threads. And none from the usual trolls.

How can you add anything to infinity when it’s precisely meaning the ultimate, endless?

c’mon

logic

See what I mean? Mr Vora, and everyone else!?

What the heck!?

Try reading the Maths from Vora, and reason with logic, instead of your emotions!

nahhh.. there was definitely staged landings, AS WELL most certainly actual ONES.

This also makes me wonder if the tangent of 90 is equivalent to 3 divided by 0.

…far before ‘69

I know infinity means endless, and therefore nothing as like a + 1 to be added

logically speaking 

is concrete

You're being dishonest now as well as a...

Infinity i+1, cannot be broken down any further, as opposed to infinity+1 which remains just infinity.

What are you doing, Sir?

oh wait.. lol wtf is that i for in front of infinity sign? 😂 …had I seen that lmao yeah I wouldn’t waisted a post here sure

I lol thought it was typed ♾ +1