What is ♾️+i?

i being the "imaginary unit." Also known as the square root of, -1.

idk

Let give infinity + (i) = X

Then (infinity + (i))² = X²

infinity² + 2(i)(infinity) + i² = X²

infinity + 2(i)(infinity) -1 = X²

infinity + 2(i)infinity = X²

2th root of p+qi is equal ±(a+bi) when a² = 0.5( p+[p²+q²]⁰'⁵ ) and b² = 0.5( -x+ [p²+q²]⁰'⁵ ) and 2abq > 0

So from the infinity + 2(i)infinity = X² will get

a² = 0.5( infinity + [infinity² + (2infinity)²]⁰'⁵ ) = infinity

a = ± infinity

b² = 0.5( -infinity + [infinity² + (2infinity)²]⁰'⁵ ). from the initial polynomial distribution make in this expression make infinity~infinity (only this equation*), so [infinity² + 4(infinity)]⁰'⁵ ~ [infinity² + 4(infinity) + 4]⁰'⁵ ~ [(infinity+2)²]⁰'⁵ = infinity+2. So b² ~ 0.5(-infinity + (infinity+2)) ~ 1

b => Real number (give b=R~1)

From 2abq > 0 ; 2a(R)(2infinity). So a>0 ~ infinity

Therefore a±bi = ± [infinity + R(i)] = infinity ± (R)i

CONCLUDE : "infinity + i" is already in simple form.

I can say thay infinity is not equal to infinity+(i) because infinity is the extension of real numbers only. So complex numbers are a much and much larger number system. so that the result of infinity+(i) is definitely not in the scope (or extension) of real numbers.

Or if you insert a complex number into the 2D perpendicular coordinates, you will find that this number is definitely not equal.

Do you know if tan(90)=3/0 is a true statement? I did ask this on the other thread, but I fear it got lost among the other replies.

Why don't you Google it yourself?

No, way!

https://www.google.com/search?q=tan+90&oq=&aqs=chrome.1.69i57j6j0i512l7.5744j0j4&client=ms-android-verizon&sourceid=chrome-mobile&ie=UTF-8

Infinity+i = infinty, anything added  to or subtracted from infinty still stays infinity

Infinity i+i=infinity i

Infinity i+1 just equals infinity i plus 1.

infinity i+x, when x is a real number, remains infinity i+x.

It is a stain to type on the cell phone, so quit wasting my time.

Are you all this bad at testing your theories to failure, when over the Chess Board?

Infinity+i=ComplexInfinity

Infinity i+1 is still ComplexInfinity

There are exactly 8 times as many numbers in the Complex number set, as there are Reals.

The Largest Possible Complex Infinities are +/-infinity, +/-infinity i

+/-infinity+/-infinity i 

Apparently, tan(90) simplifies to 1/0, so the simplified equation is 1/0=3/0. I do think these are equivalent, but since both do not have a defined answer, I can't be certain.

Four times as many if you compute both infinity, and -infinity

Nope.

According to that link I shared it computes to this.

 -1.99520041221

Where did you get "1/0" from?

I think @DragonGamer231 means tan(90 degree) = 1/0

However tan(90) = tan(90 radian) = -1.9952...

These numbers are beyond my imagination. I'm not sure my proof is correct. I'm proving that it's an incremental polynomial (Think of X as a variable and the rest as constants) that cannot be attenuated in a infinity complex number system.