According to http://www.chess.com/tournaments/help.html#tiebreak:
Group #-- | 1 | 2 | 3 | Points | Tie Break |
---|---|---|---|---|---|
1. Bob | X | 1 1 |
0 1 | 3 | 4.5 |
2. John | 0 0 | X | 1 0.5 | 1.5 | 2.25 |
3. Mary | 1 0 | 0.5 0 | X | 1.5 | 3.75 |
A player's tiebreak score is calculated by adding the sum of the player's points they have defeated to half the sum of the player's points they have drawn against.
Bob won two games against John and one game against Mary. So Bob gets 2x1.5 points from John and 1.5 points from Mary, which sums up to 4.5 tiebreak points.
John won one game and drew one game against Mary. So John gets 1.5x1.5 points from Mary, which sums up to 2.25 tiebreak points.
Mary won one game against Bob and drew one game against John. So Mary gets 1x3.0 points from Bob and 0.5x1.5 points from John, which sums up to 3.75 tiebreak points.
I hope this helps.
I have looked on the forums and I can't find anything on tie-breaks in tournaments. Can someone explain this to me.
I am currently in a tournament (trials of the best). I have a record of 11-3-1, and the player ahead of me has a record of 11-4-1. We each have a score of 11.5. We split our two games with a win apice. The only thing I can see different is he has a tie-break score of 80.25 and I have a tie-break score of 75.25.
With a better record it seems like I would be in first place and he would be in 2d.