Why did I not advance in this tournament?

Sort:
mbcnorse13

Hi All,

Going from Round 7 to Round 8 in a tournament.  Up until this point groups had been either 3 or 4 people, with the top two in the group always advancing to the next round.  In this last round (6 total people left, 2 groups of 3 each) I took second in the group but, for some reason, did not advance to the next round.  Any idea why?  See attached screenshot for reference.

Thanks!

Martin_Stahl
mbcnorse13 wrote:

Hi All,

Going from Round 7 to Round 8 in a tournament.  Up until this point groups had been either 3 or 4 people, with the top two in the group always advancing to the next round.  In this last round (6 total people left, 2 groups of 3 each) I took second in the group but, for some reason, did not advance to the next round.  Any idea why?  See attached screenshot for reference.

Thanks!

 

The maximum that can move forward in any round is half the group size, rounded down, regardless of the number advancing in the beginning of the tourney. So, since the group sizes are 3, the max moving forward is 1, with the exception being that ties move forward as well.

mbcnorse13
Martin_Stahl wrote:
mbcnorse13 wrote:

Hi All,

Going from Round 7 to Round 8 in a tournament.  Up until this point groups had been either 3 or 4 people, with the top two in the group always advancing to the next round.  In this last round (6 total people left, 2 groups of 3 each) I took second in the group but, for some reason, did not advance to the next round.  Any idea why?  See attached screenshot for reference.

Thanks!

 

The maximum that can move forward in any round is half the group size, rounded down, regardless of the number advancing in the beginning of the tourney. So, since the group sizes are 3, the max moving forward is 1, with the exception being that ties move forward as well.

 Thanks for the response, but it still does not seem right.   Take a look at this screen shot from the same tournament one round earlier?  Two people from each group advance despite there not being a tie... thoughts?

manekapa

For the round #6, which you referenced in post #3, the first group did have four players.

https://www.chess.com/tournament/the-butchers-knife-cares-not-for-the-lambs-cry/pairings/6

mbcnorse13
manekapa wrote:

For the round #6, which you referenced in post #3, the first group did have four players.

https://www.chess.com/tournament/the-butchers-knife-cares-not-for-the-lambs-cry/pairings/6

But what does the first group having 4 players have to do with players from group 2 and 3 advancing?  I am trying to understand why, in round 6, there are two groups of three players each that have two players advancing (shown in my screen shot).  Then, in round 7, my group of 3 players only had 1 player advance.  Why?  How does one know how many players will advance in a 3 person group?

manekapa
mbcnorse13 wrote:
manekapa wrote:

For the round #6, which you referenced in post #3, the first group did have four players.

https://www.chess.com/tournament/the-butchers-knife-cares-not-for-the-lambs-cry/pairings/6

But what does the first group having 4 players have to do with players from group 2 and 3 advancing?  I am trying to understand why, in round 6, there are two groups of three players each that have two players advancing (shown in my screen shot).  Then, in round 7, my group of 3 players only had 1 player advance.  Why?  How does one know how many players will advance in a 3 person group?

According to the formula Martin cited, for a group of three players, half rounded down means one player will advance from the group.

However, round six and seven were different because round six had a four player group.

For round six, the number of advancing players was four divided by two. It looks like the largest group determines the number of advancing players for every group in a round. It wouldn't be fair to penalize the players in the smaller groups of a round.

In round seven, both groups were the same size of three players. Therefore, only one advanced from each group in that round.

NubbyCheeseking

If I'm correct, only 3 people can be in the group, so they took the top 2 from each group and calculated the top 3 out of those 4.

It's just my guess though

mbcnorse13
manekapa wrote:
mbcnorse13 wrote:
manekapa wrote:

For the round #6, which you referenced in post #3, the first group did have four players.

https://www.chess.com/tournament/the-butchers-knife-cares-not-for-the-lambs-cry/pairings/6

But what does the first group having 4 players have to do with players from group 2 and 3 advancing?  I am trying to understand why, in round 6, there are two groups of three players each that have two players advancing (shown in my screen shot).  Then, in round 7, my group of 3 players only had 1 player advance.  Why?  How does one know how many players will advance in a 3 person group?

According to the formula Martin cited, for a group of three players, half rounded down means one player will advance from the group.

However, round six and seven were different because round six had a four player group.

For round six, the number of advancing players was four divided by two. It looks like the largest group determines the number of advancing players for every group in a round. It wouldn't be fair to penalize the players in the smaller groups of a round.

In round seven, both groups were the same size of three players. Therefore, only one advanced from each group in that round.

Hi Manekapa, thanks for taking the time to respond!  That makes sense, I guess I just was not aware of the rule that if the max group size was 3, only 1 person could advance from each group (excluding ties).  And since every previous round in this tournament (my first) had had at least one group of 4, I assumed that the top 2 would always advance.

Too bad for me, but thanks, again!

tonyklemm

I was curious of how this works when it gets to the latest rounds of play. I've joined a few tournaments in the last few months but none have reached this stage yet.