What happens with the 1. killer?
a fight between the 1. and the last?
What happens with the 1. killer?
a fight between the 1. and the last?
i could not get you..!
off the top of my head 9 don't know Y just a guess . I'll check my answer & get back with U.
ha ha.. okk.. but here the answer is also posted by COSINE, from Canada.
I saw that but (he he butt) i don't quite get it I'll have 2 put it on paper,
I mean my math skills have tested 2 b equivalent 2 a 9th grade student.
How hard can it B?
Or you could, you know... Just say it has to be 977 by process of elimination.
Holy Christ...
Or you could, you know... Just say it has to be 977 by process of elimination.
Holy Christ...
but that's not the smarter way..
Hmm... so the first 500 killed are even, the 250 killed are every second odd, the 125 killed are every fourth odd... This is confusing me. And then the 62 killed are every sixth odd + 1. I'm out. I'm just guessing it has to be 2expx multiplied by x minus 1 (No, I actually did some calculations.). IT must be... 513
There are 1000 people standing in a circle,with numbers printed on their shirts(consecutive numbers from 1 to 1000). number 1 has a sword. He kills the 2nd and gives it to num 3. 3 kills 4 and passes the sword to 5. This process continues until there is only one person remaining. Can u tell what's that person's number ?