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hey..!! try this logical puzzle...!!!

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kunduk

Crack this..
There are 1000 people standing in a circle,with numbers printed on their shirts(consecutive numbers from 1 to 1000). number 1 has a sword. He kills the 2nd and gives it to num 3. 3 kills 4 and passes the sword to 5. This process continues until there is only one person remaining. Can u tell what's that person's number ?

pskogli

What happens with the 1. killer?

a fight between the 1. and the last? 

kunduk
pskogli wrote:

What happens with the 1. killer?

a fight between the 1. and the last? 


i could not get you..!

kunduk

you can ask various questions related to this prob..!

kunduk

absolutely right..!!!

kunduk

@cosine, excuse me, but are you a mathematician? anyways, CONGRATS...!!!

rooperi

I didn't get much of that, but it certainly sounds impressive.

deanie
kunduk wrote:

 

Crack this..
There are 1000 people standing in a circle,with numbers printed on their shirts(consecutive numbers from 1 to 1000). number 1 has a sword. He kills the 2nd and gives it to num 3. 3 kills 4 and passes the sword to 5. This process continues until there is only one person remaining. Can u tell what's that person's number ?

 


off the top of my head 9 don't know Y just a guess . I'll check my answer & get back with U.

kunduk

ha ha.. okk.. but here the answer is also posted by COSINE, from Canada.

deanie
kunduk wrote:

ha ha.. okk.. but here the answer is also posted by COSINE, from Canada.


 I saw that but (he he butt) i don't quite get it I'll have 2 put it on paper,

I mean my math skills have tested 2 b equivalent 2 a 9th grade student.

How hard can it B?

Ketamine
Cosine wrote: Lots of crap that makes him seem smart here.

Or you could, you know... Just say it has to be 977 by process of elimination.

Holy Christ...

kunduk
Ketamine wrote:
Cosine wrote: Lots of crap that makes him seem smart here.

Or you could, you know... Just say it has to be 977 by process of elimination.

Holy Christ...


but that's not the smarter way.. Wink

Ketamine

Nerds are so cute!

kevinjin

Hmm... so the first 500 killed are even, the 250 killed are every second odd, the 125 killed are every fourth odd... This is confusing me. And then the 62 killed are every sixth odd + 1. I'm out. I'm just guessing it has to be 2expx multiplied by x minus 1 (No, I actually did some calculations.). IT must be... 513

ShadowIKnight

Oh i think ive got it. It must produce a list of lucky numbers. Oh no wait, then there cant be one left standing... lol :P

ShadowIKnight

for the nerds http://brainden.com/forum/index.php?/topic/7688-last-man-standing/ :P