accuracy algorithm

Hi folks! Anybody knows if it is possible to have absolutely equal accuracy of the game if both gamers didn't  use any program/engine?  Because if it just counts the percentage of the best moves, it is rather impossible to arrive at the same accuracy at the end, considering there were 33 moves, so not a short game.

Thanks in advance

That doesn't really seem possible. Equal positions could happen mid-game, but to remain equal the entire game seems impossible. First of all, odd-numbered moves like you pointed out, or ply (one side moving before the other side moves) giving one color an extra move than the other. These details would sway the advantage even if just temporarily. Chess is also currently unsolved; meaning that no computer has worked out all of the possibilities, so it wouldn't even be feasible to know how to even continue an equal position, or how that would even look.

A similar question is with optimal play from both sides, is chess a draw? This is highly debated, but it's all theoretical.

sorry, there are 34 moves,not 33

The "precision" or "accuracy" calculation used by this chess site has only a tangential connection to the actual value of the moves.

A game evaluated at 80 accuracy for a 700 rated player might only be assigned 50 accuracy for a 1600 rated player.

So what does it mean? Which probability is to have absolutely equal accuracy for the game for both gamers with different rating?

If you are talking about the percentage accuracy stat, then none.

That isn't its purpose. It's basically a feel-good stat.

I'm not sure that I even understand your question.

How do you define "precision"? Move matches to the computer's own top choice? But that changes with every new version of the computer software... does that mean that the definition of precision changes, and a move that was "accurate" is no longer accurate?

I wouldn't take either of those numbers very seriously.

Precision comparison is meaningless. You are taking two different test papers. It is not like you are both doing the same puzzle rush sequence.

Impossible to answer. It's still unclear what you mean by "precision".

I mean the accuracy (in English) in the analysis of chess.com. Excuse me my English, in Italian is "precisione"

Okay, so then it's possible to answer.

Accuracy is some integer number that usually (but not always) is between 40 and 90. So the chance that both players have the same number is roughly 2 percent. Unlikely, but obviously not even close to "impossible".

Actually it is not an integer, but thank you for the answer!

Oops, I made a mistake. Accuracy is not an integer, but instead it's one decimal. (Shows how often I use Game review - never).

So the probability is one-tenth of what I said. Sorry.

Your math is only good if you want an exact number for both players. (For example, 66.6 for both). If any number is good, then it's just 2 / 1000.

But the topic is about the exact number

As I read it, it wasn't. It was about that both accuracies are the same, whatever that number is.

Nobody knows exactly how the accuracy calculation works. It's chess.com's secret. Probably very complicated.

You are calculating it as if there was only ONE way to match the two numbers.

ie: as if ONLY 60.3 vs 60.3 counted.

Try multiplying your answer by 1001. Or if you are only counting the range 40-90, by 501.