What was dishonest about you though, is you took the time to make posts like this, instead of correcting me. If this is a win for you, you should thank btickler, not yourself. And again, imo, this is still you deflecting and conceding from the points i made, which are still relevant to your post in question. I'm waiting for you guys to start talking about food again like you've done in other threads to avoid having to retort the points I have made.
More than one person immediately pointed out your error but you blew us off with "I can't be bothered to actually look at the posts", or "you guys are all just trolls" or other such crap and now complain that nobody explained things to you. Any time anyone does explain something to you you engage in slurs, off-the-subject rants, incoherent babble and repetition of things you have already said 100 times.
To quote Toshiro Mifune in Akira Kurosawa's classic film "Yojimbo", "You can't help fools."
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Chess is indeed an exact mathematical problem. There is a finite set of 10^44 legal positions with subsets of 32, 31... 9, 8, 7, 6, 5, 4, 3, 2 men. There is also a relation 'position (FEN) B can result from position (FEN) A' according to the Laws of Chess. So solving chess is finding a path from the initial position towards either a known 7-men draw, or a dead end of 3-fold repetition.
There are approximately 4.82 x 10^44 basic rules legal positions (FEN - ply count).
You say you plan to solve chess under competition rules.
In that case there there are approximately 7.27 x 10^46 FENs associated with game states (Tromp's number for basic rules must be multiplied by the 151 different values of play count that may be associated with positions that don't exceed the mandatory 75 move rule).
There IS NOT a well defined relation 'FEN B can result from FEN A' under competition rules.
FEN A will be associated with many different situations that can occur in a chess game depending on how the situation is arrived at.
If it's associated with a situation that has been arrived at via four previous situations that match the associated basic rules position then no FEN B can result because the game immediately terminates under the mandatory quintuple repetition rule.
If the same FEN A is associated with a situation that is not so arrived at then it will result in situations with different FEN Bs. But for each such FEN B not all situations having FEN B can be arrived at, because the moves leading to those situations may not be extensions of the moves leading to the situation which is associated with FEN A.
I would call the "situations" I talk about "positions" in the competition rules game (and my interpretation of the FIDE laws is that the two are in general taken to mean the same). You would not, but in that case you cannot Identify positions with the nodes in your search space. It's the number of such nodes that is important in determining the feasibility of a solution based on a forward search. Rather than quibble over the meaning of "position" I'll just refer to nodes (no doubt much to @playerafar's disgust).
If the nodes are defined as a FEN together with the set of basic rules positions that have occurred since and including the last node associated with a ply count 0 FEN and a multiplicity (1-4) for each node, then there IS a well defined relation 'node B can result from node A' under competition rules. This relation defines the game tree (an abuse of language, it's actually a directed graph) and the solution.
The number of nodes in the game tree is therefore the number of equivalence classes of legal PGNs from a ply count 0 position, where PGNs are taken to be equivalent if they result in the same associated basic rules positions each with the same multiplicity and have the same final basic rules position. (The PGNs are also what you need to pass to an engine over the UCI interface if is to function correctly - assuming it's capable of avoiding triple repetitions when it thinks it's winning.)
It's apparent that the number of nodes in the search space under competition rules is vastly hugely humongously greater than 7.27 x 10^46. There is an obvious upper bound of 4.82 x 10^44 x 3^(4.82 x 10^44) but it's very easy to reduce this very substantially by summing over endgame classifications and some further considerations. I did invite you to propose a reduced upper bound with no response. Do I need to do it for you? (Notice nodes beyond the 50 move rule and triple repetition rules are excluded from that upper bound because continuations when these conditions occur can be pruned. Also no factor is included for the ply count because that is the sum of the repetition counts so already accounded for.)
So solving chess obviously depends on the version of chess, The game tree determines the solution and the game trees are different under basic rules and competition rules. In particular your known 7 man draws are different, so you're aiming for different destinations in the two games.
Also the position you posted in #296 is a draw under competition rules, so you should have included a 50 move rule draw under your termination conditions, not to mention a dead position.
But your description is naff to start off with. I can give you any number of paths towards either of the things you mention. If that's all you want to do what are the supercomputers about?