Yeah, a king would never has less than 8 free squares if both the top and bottom are connected and also the sides are connected.
For example on a1 the king could move to the usual 3 squares plus h1, h2, a8, b8, and h8 for a total of 8.
So to mate will always require opposing the king + rook to control 9 (8 free squares plus the one the king is standing on).
However the rook gains no additional mobility from a globe construction. In fact we can more easily visualize any attempt at checkmate by placing the pieces in the middle of a standard board... and we already know K+R mate cannot happen in the middle of the board.
I think the question is self, explanatory. In this scenario there couldn't possibly be a Rook and King vs King #.