Qb7 ??? how about that ??
Mate in 2 with a paradoxical idea
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Feb 12, 2012
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#23
Therell wrote:
Qb7 ??? how about that ??
Qxb7+ is met by Kxb7. Losing your Queen is not good in this situation.
ANason21 wrote:
Therell wrote:
Qb7 ??? how about that ??
Qxb7+ is met by Kxb7. Losing your Queen is not good in this situation.
Ok I realized it now... Thanks
If I got it right, any of Qa4, Qd4, Qe5 moves is a mate in 1. Of course, besides Qh1.
Nope. Ra6+ and after something takes the rook, bxa6 keeps it from being a mate in 2. Similarly, if the king moves out of check, it isn't a mate in 2. You have to maintain the pin of the b pawn, which means the queen has to stay on the a8-h1 diagonal.
I disagree. Putting the Queen on either the a file or the 8th rank (i.e., Qa4 or Qe8) works too, notwithstanding releasing the pin on the pawn. Point is, RxQ is met in either case by RxQ#, while if not RxQ (for example, a pawn move to either b6 or b5), then QxR#. And if Qa4 is met by Re8+, then Rxe8#. So it is a mate in two, but with more than one solution.
See the edit. On further analysis, any move other than Qh1 allows Ra6+, delaying mate. So Qh1 is the only way to mate in two.