0.9999 repeating is equal to 1 - and i can prove it

So, is that the prove to the question to this forum thread topic? 

Uhhhhh...

firstly You're just making complicated things even more complicated by multiplying 0.999... by 2 

Secondly 0.999... x2 not equals 1.88888

It's 0.999 repeating 

Not 999/1000

Then, don't round it to 10 right now, wait until the best time to round it silly

999 Ad infinitum does not ever become 10^infinity

And 0.999  Ad infinitum never dissolves into 1.

Hope that helps.

Subtract 0.999...from 1, and you get 1/infinity, not 0.

1/infinity never approaches 0 or becomes it.

"If 9.9999 repeating is equal to 10x."

Therein lies your fault, 9.9999 repeating is NOT equal to 10, and you cannot prove it. And you don't even know it.

Time for an explanation of infinite sets.  Something is infinite if you can count it using integers starting at one and continuing on forever without missing anything you are counting.  For instance, the set of positive numbers is infinite.  Also, the set of even numbers is infinite (2 can be the first number counted, 4 the second, and so on forever.  The set hundredths is infinite (0.01 can be the first number counted, 0.02 the second, and so on forever).

The following are infinite sets that are equal because they can all be numbered by the infinite set of positive integers:  infinity, infinity*100, infinity/100, infinity+1000, infinity-1000, infinity squared (think of it as cartesian coordinates with the first coordinate being 1,1 the second 2,1, the third 1,2, the fourth 3,1, the fifth 2,2, the sixth 1,3 and so on to infinity), infinity raised to any finite power, etc.

.(repeating 9) means an infinite number of 9s after the decimal point.  Let that be X.

When you multiply .(repeating 9) by ten then the decimal point shifts and it become 9.(repeating 9) still with an infinite number of 9s after the decimal point.

Thus 10X - X = 9.(repeating 9) - .(repeating 9), which reduces to 9x = 9 and dividing both sides by 9 makes it X=1.

Alternatively, set X=1/9 = 0.(repeating 1)

Multiply by 9 and you get 9X=9/9 = 0.(repeating 9) and 9/9 = 1

".repeating 9) means an infinite number of 9s after the decimal point. Let that be X."

Hmm let what be X, exactly?

It's just short, but very close.

Almost any demonstration that 0.(infinitely repeating 9) = 1 requires the audience to understand infinity and algebra.

Without that understanding any further comment is a waste of time.

The concept of algebra and infinitely repeating sequences is standard math.

If you let x = 0.(infinitely repeating 6-digit sequence 142857) then you can turn that into a fraction as follows

1,000,000x = 142857.(infinitely repeating 6-digit sequence 142857)

1,000,000x - x = 142857.(infinitely repeating 6-digit sequence 142857) - 0.(infinitely repeating 6-digit sequence 142857)

thus 999,999x = 142857

dividing both sides by 142857 gives

7x = 1

x = 1/7

People who cannot follow those equations will not be able to follow the statement from the OP.

Nope it never reaches the finish line, since a line to infinity is unreachable.

A line to infinity may not be reachable, but it is definable.  If two such lines are definable the same way (after the first one digit or first ten digits or first billion digits) then the difference between them is very reachable.  To understand the math a person has to first understand the mathematical definition of infinity.

Nope.

As I've stated earlier. 9999...ad infinitum does not touch 10^n no matter how many "9's" you place. Anymore than 0.999 ad infinitum ...reaches 1.

Both parties need an understanding of the mathematics of infinity for a discussion to be worthwhile.  This discussion is over due to that lack of understanding.

What do you mean this conversation is over?

Who are you to decide?