1/infinity is not equal, to 0
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The real part of both of those complex numbers are equal to infinity. Any complex number that has either the real or imaginary part equal to infinity is not a number
Apr 2, 2023
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#22
Lincoy3304 wrote:
The real part of both of those complex numbers are equal to infinity. Any complex number that has either the real or imaginary part equal to infinity is not a number
Oh yea,
Prove it.
Apr 2, 2023
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#23
Lincoy3304 wrote:
The real part of both of those complex numbers are equal to infinity. Any complex number that has either the real or imaginary part equal to infinity is not a number
What is, let's say, 1+(i/infinity)? - I/infinity being an infinite number. Infinitely small, but not equal to infinity.
Is infinity a number or no? This will decide how I continue talking to you
Apr 3, 2023
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#25
Lincoy3304 wrote:
Is infinity a number or no? This will decide how I continue talking to you
Well is the absolute value of the ratio of the two numbers, (1/0) , equal infinity? Why, yes.
So who are we to say infinity cannot be a number?
The ratio of two numbers two each other does not define that the outcome is a rational number, let alone a number. You may ask me to prove that, but I will ask you to look it up first
Apr 3, 2023
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#27
Lincoy3304 wrote:
The ratio of two numbers two each other does not define that the outcome is a rational number, let alone a number. You may ask me to prove that, but I will ask you to look it up first
Not a "rational" number, but the quotient of 2 real rational numbers, being defined as the endless.
Mathematicians do not define it because 0 cannot go into 1 regardless of how many times you do it. Another reason is because 3/0=4/0=5/0=…=n/0 where n is any number.
Also, if 1/0 is + or - infinity as you say, then 1/0^-1 equals 1/(1/0)=0/1=0
Replace 1/0 with infinity and you get 1/♾️=0
Also, if 1/0 is + or - infinity as you say, then 1/0^-1 equals 1/(1/0)=0/1=0
Replace 1/0 with infinity and you get 1/♾️=0
Apr 3, 2023
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#29
Lincoy3304 wrote:
Mathematicians do not define it because 0 cannot go into 1 regardless of how many times you do it. Another reason is because 3/0=4/0=5/0=…=n/0 where n is any number.
Also, if 1/0 is + or - infinity as you say, then 1/0^-1 equals 1/(1/0)=0/1=0
Replace 1/0 with infinity and you get 1/♾️=0
Also, if 1/0 is + or - infinity as you say, then 1/0^-1 equals 1/(1/0)=0/1=0
Replace 1/0 with infinity and you get 1/♾️=0
Nope 1/0 can said to be +/- infinity, because (1/0)*0=0/0 which is any any Complex number. While infinity*0 equals infinity*(1-1+i-i)=infinity-infinity+infinity i-infinity i=any Complex number.
So they equal the same thing. See?
Apr 3, 2023
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#30
As for your last statement.
(1/♾️)^-1=♾️
While
(-1/♾️)^-1=- ♾️
Showing that they do differ, and cannot equal the same amount, or only Zero.
That method might be correct, but you still have to explain my method as being incorrect and why it is.
I said ♾️^-1 equals 0 according to your definition, not 1/♾️^-1
Both of ours
Its the same thing intellectual. Why is mine incorrect and yours correct if we both have correct proofs?
Apr 4, 2023
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#37
Lincoy3304 wrote:
That method might be correct, but you still have to explain my method as being incorrect and why it is.
What # post would that be?
#28
Apr 4, 2023
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#39
"Mathematicians do not define it because 0 cannot go into 1 regardless of how many times you do it."
Name a Mathematician that doesn't. I can
(1/0)*0 equals any number.
"Another reason is because 3/0=4/0=5/0=…=n/0 where n is any number."
Why should the Natural Numbers just be included?
I am guessing you did not figure out that;
1/0=-2/0=i/0=0.9/0 will equal any non 0 denominator over 0
"Also, if 1/0 is + or - infinity as you say, then 1/0^-1 equals 1/(1/0)=0/1=0
Replace 1/0 with infinity and you get 1/♾️=0."
Here is your worst fault.
0 is equal to +/-1/infinity, but 1/infinity is only positive and not equal to 0.