77 + 33 = 100
Sort:
Alp1ne14
Feb 24, 2025
0
#1
It’s true
Feb 24, 2025
0
#2
1 = 1
A = A
A = B
A * A = A * B
A^2 = AB
A^2 - B^2 = AB - B^2
(A+B)(A-B) = B(A-B)
A + B = B
B + B = B
2B = B
2 = 1
A = A
A = B
A * A = A * B
A^2 = AB
A^2 - B^2 = AB - B^2
(A+B)(A-B) = B(A-B)
A + B = B
B + B = B
2B = B
2 = 1
Feb 24, 2025
0
#4
If 2 = 1, then 1 = 0. If 1 = 0, then 110 = 0 and 100 = 0. If that’s the case, 110 = 100. 77 + 33 = 100.
Believe it or not, second-grade addition works also.
Feb 24, 2025
0
#8
@GeorgeIngo
1+1=1+sqrt(1)
1+sqrt(1)=1+sqrt(-1)*sqrt(-1)
1+sqrt(-1)*sqrt(-1)=1+i*i
1+i*i=1+i^2
i^2=-1
1+i^2=1+(-1)
1+(-1)=1-1
1-1=0
Therefore, 1+1=0
1+1=1+sqrt(1)
1+sqrt(1)=1+sqrt(-1)*sqrt(-1)
1+sqrt(-1)*sqrt(-1)=1+i*i
1+i*i=1+i^2
i^2=-1
1+i^2=1+(-1)
1+(-1)=1-1
1-1=0
Therefore, 1+1=0
Feb 24, 2025
0
#12
Yeah and when u are square rooting a number, the function is only defined for nonnegative numbers
Feb 24, 2025
0
#13
Alp1ne14 wrote:
1 = 1
A = A
A = B
A * A = A * B
A^2 = AB
A^2 - B^2 = AB - B^2
(A+B)(A-B) = B(A-B)
A + B = B
B + B = B
2B = B
2 = 1
A = A
A = B
A * A = A * B
A^2 = AB
A^2 - B^2 = AB - B^2
(A+B)(A-B) = B(A-B)
A + B = B
B + B = B
2B = B
2 = 1
wait this completely falls apart on step 8
Is this forum for kids?
