Wut?
|1/0| is Positive Infinity.
Yet |1|/|0| is both Negative and Positive.
But perhaps , 1/0 is a Greater Number than regular Infinity. For 0 is less than (1/infinity) in it's absolute value.
Example
Infinity^-1 will equal 1/infinity. While (-infinity/1)
will equal -infinity.
From this we devise that 1/infinity is different than 0, and not as small, therefore.
Anything divided by 0 is undefined. Though it approaches infinity if you investigate division by 0 in terms of limits, infinity cannot be reached in reality.
Also, after applying the absolute value, if you divide both sides by 0 to move the 0 from the left to the right, the equation will become 1= infinity*0. The problem here is that we also have a rule saying anything times 0 equals 0. With infinity, anything multiplied by it is either undefined or infinity. So now we have three solutions shouting at us:
Copied off the internet.
First off,
For your last statement. It is wrong.
0 can be reached from division because ((1/(1/0)) shall equal 0.
But 1/infinity is more, because 1/(1/infinity) is infinity. But not negative infinity as -1/(1/infinity) is.
infinity x 0 is covers all Real Values.
Because; infinityx0 will equal infinity x (1-1) equals infinity-infinity equals any Real Value.
See if you can deduce why, yourself.
|1/0| which equals the "Absolute Value" of; 1/0, which is Positive Infinity.
|1/0|*i is the Square Root of -|1/0| for further clarity.