ASK ME MATH QUESTION

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Avatar of carrotboy1234
Just to clear up any confusion, the vertex of y = 15x^2 + 4x + 92 is located at (-0.1333…, 91.7333…) https://www.desmos.com/calculator/kvvoxrll56
Avatar of Peskybird_flies
#119
But it was a parabola
The vertex of a parabola is either the highest or lowest
I literally just said that I didn’t know if it was called something else for different situations. I get what it is
Avatar of Peskybird_flies
#122
Eh?
I don’t think supposed to get .133….. and .73….. in the answer
Avatar of jumpy_snake123
Oh my god
Avatar of KyngKiller

How many possible positions are in a chess game according to FIDE rules?

Avatar of Peskybird_flies
#126
A lot
Avatar of carrotboy1234
#124 can also be written as (-2/15, 1376/15) or (-2/15, 91and11/15 [mixed fraction])
Avatar of Peskybird_flies
I get that it can be written as a fraction
Where the heck did u get it from tho?
Avatar of carrotboy1234
See Desmos link in #122, or use x = -b/2a and then sub that to find y
Avatar of 1AncientConcavenator
Trigonometry (bearings)
A hiker leaves a campsite and walks 7 km on a bearing of N 40° E (that’s 40° east of due north). Then, she turns and walks 10 km on a bearing of S 60° E (60° east of due south). How far is she from the starting point?
Avatar of Peskybird_flies
#131
17km?
Avatar of Peskybird_flies
Wait, nvm
That don’t work
Avatar of 1AncientConcavenator
c^2 =a 2 +b^2 −2abcos(C) is the equation
Avatar of Peskybird_flies

I was just gonna do a^2+b^2=c^2

When I did that, I got a lil over 12km (…)
Avatar of carrotboy1234
#134 or resolve into north components and east components, add then c^2 = a^2 + b^2
Avatar of 1AncientConcavenator
If I did my math correctly it should equate to 13.16
Avatar of Peskybird_flies
#136
That was what I was thinking
Avatar of carrotboy1234

I like maths too much

Avatar of 1AncientConcavenator
#139 Math Chad. Also that’s correct
Avatar of playerafar
Peskybird_flies wrote:
#119
But it was a parabola
The vertex of a parabola is either the highest or lowest
I literally just said that I didn’t know if it was called something else for different situations. I get what it is

No. The parabola could be on its side. Pointing to right or left.
But then the equations are more difficult.
The point is that you then do not have the vertex at top nor bottom. It points sideways.
'the point'. Pun not intended but the pun works anyway.
the one opening to the right can be written x = y^2
the one opening to the left can be written x = -(Y^2)
But that's not proper y=f(x) notation which involves square roots and +- signs which my keyboard doesn't do well.