Complex Infinite Numbers
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Jun 20, 2021
0
#2
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Jul 17, 2021
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#5
Wait aren’t they the same? Can’t you get every prime number by multiplying prime numbers with other prime numbers and just add 1 to it? I’m confused why
Jul 17, 2021
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#6
Because if the infinity of even numbers were larger than prime numbers,there would be no algorithm omnhow top calculate every even number, which is just 2x
Jul 17, 2021
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#7
Take an example between the infinity of the integral numbers and the rational numbers. These are both equal, because there is a pattern/algorithm to calculate every numbers. With the integral numbers it’s just by adding 1. with the rational numbers it’s a bit harder. I imagine a grid. Let the horizontal axis be the denominator of a rational number, and the Vertical axis the numerator. Now, if every coordinate on this grid would be a fraction(example coordinate 2/1 would be 1/2) every rational number would be on the grid. And because every number of these sets can be displayed, they are equal
Oct 13, 2021
0
#8
Andrew_Stephenson wrote:
If i can be denoted as the square root of -1, also named the imaginary unit, then infinity i plus 3, is a complex Infinite number.
Likewise infinity + 3i is a complex Infinite number.
Was this properly formulated?
Lol, MarkOfGreatness you copied that from my thread
Oct 15, 2021
0
#10
The square root of Infinity+Infinity i, is Infinity+i
Because (Infinity+i)(Infinity+i)=Infinity+Infinity i + Infinity i-1= Infinity + Infinity i
But the square root of Infinity i, itself yields an indeterminate result.
Oct 15, 2021
0
#11
Andrew_Stephenson wrote:
The square root of Infinity+Infinity i, is Infinity+i
Because (Infinity+i)(Infinity+i)=Infinity+Infinity i + Infinity i-1= Infinity + Infinity i
But the square root of Infinity i, itself yields an indeterminate result.
Come on guys post something more.
The quoted text above is probably a "Theoretical Novelty." - In Mathematics that is.
If i can be denoted as the square root of -1, also named the imaginary unit, then infinity i plus 3, is a complex Infinite number.
Likewise infinity + 3i is a complex Infinite number.