Give me math problems!

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Avatar of Mid-KnightRider
Rebootd wrote:

Explain the reasoning behind Stirling’s approximation without looking it up.

make children cry.

Avatar of GraysonKellogg

It depends on what difficulty problems you'd like. But, I can give you some math problems that should hopefully not be too bad. If you'd like some that are easier or harder, you can ask, but here are a few to start.

1. Explain why the derivative of f(x) = x is 1.

2. Simplify* the expression (x + 5)(x - 5).

3. Given that an integration operation reverses the derivative, why must we add "+ C" at the end of our solutions to indefinite integrals?

Avatar of Rebootd
#42 2. x^2-25
Avatar of Rebootd
Very simple stuff
Avatar of The_Erkling

X=5, -5 #43

Avatar of Rebootd
#45, no?
Avatar of GraysonKellogg

#45 would be right if I set the expression equal to zero, but I was asking for it factored, not solved. The expression might not equal zero at all, as I never specified. So, #43 was correct in response to the second problem I posted.

Avatar of Rebootd
Oh wait we’re factoring, I think he meant simplify.
Avatar of Rebootd
Nvm misunderstood the question
Avatar of GraysonKellogg

Yeah, you're right, my bad, lol. Thanks for calling me out on that! I'll edit that right now.

Avatar of Rebootd
Also 1. f(1) = 1, f(2) = 2…
Avatar of Rebootd
I’m not sure how to word that
Avatar of GraysonKellogg

For problem 1, I ask, why is the derivative of f(x) = x equal to 1?

Avatar of Thruul_Mcgon

10 in base π, in decimal, fully

Avatar of GraysonKellogg

Problem 4: Explain why i^4 = 1.

(Note: i is not a variable, rather it is a complex number with imaginary part i and no real part.)

Avatar of Thruul_Mcgon

Bc ¡ is square root of -1, so ¡^2=-1. -1^2=1

Avatar of Rebootd
1. Well, as x increases by one, f(x) increases by one, that’s all I can simplify it idk
Avatar of Rebootd
Easy question,

explain why n! = (n-1)! • n
Avatar of GraysonKellogg

The factorial operation n! multiplies every number from n down to 1. This means that in order to get from (n - 1)! to n!, you just need to multiply by n, since that would be equivalent to just straight-up taking the factorial.

For example, 4! = 4 * 3 * 2 * 1 = 24. 3! = 3 * 2 * 1 = 6. Set k = 3!, so k = (3 * 2 * 1). Thus, since 4! = 4 * 3 * 2 * 1, we see that we can replace the last part with k, such that 4! = 4k. We can easily expand this to fit any factorial where n is a natural number.

Avatar of Rebootd
Yup