Give me math problems!

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Mid-KnightRider
Rebootd wrote:

Explain the reasoning behind Stirling’s approximation without looking it up.

make children cry.

GraysonKellogg

It depends on what difficulty problems you'd like. But, I can give you some math problems that should hopefully not be too bad. If you'd like some that are easier or harder, you can ask, but here are a few to start.

1. Explain why the derivative of f(x) = x is 1.

2. Simplify* the expression (x + 5)(x - 5).

3. Given that an integration operation reverses the derivative, why must we add "+ C" at the end of our solutions to indefinite integrals?

Rebootd
#42 2. x^2-25
Rebootd
Very simple stuff
Mafioso_Official

X=5, -5 #43

Rebootd
#45, no?
GraysonKellogg

#45 would be right if I set the expression equal to zero, but I was asking for it factored, not solved. The expression might not equal zero at all, as I never specified. So, #43 was correct in response to the second problem I posted.

Rebootd
Oh wait we’re factoring, I think he meant simplify.
Rebootd
Nvm misunderstood the question
GraysonKellogg

Yeah, you're right, my bad, lol. Thanks for calling me out on that! I'll edit that right now.

Rebootd
Also 1. f(1) = 1, f(2) = 2…
Rebootd
I’m not sure how to word that
GraysonKellogg

For problem 1, I ask, why is the derivative of f(x) = x equal to 1?

Hot_Rash

10 in base π, in decimal, fully

GraysonKellogg

Problem 4: Explain why i^4 = 1.

(Note: i is not a variable, rather it is a complex number with imaginary part i and no real part.)

Hot_Rash

Bc ¡ is square root of -1, so ¡^2=-1. -1^2=1

Rebootd
1. Well, as x increases by one, f(x) increases by one, that’s all I can simplify it idk
Rebootd
Easy question,

explain why n! = (n-1)! • n
GraysonKellogg

The factorial operation n! multiplies every number from n down to 1. This means that in order to get from (n - 1)! to n!, you just need to multiply by n, since that would be equivalent to just straight-up taking the factorial.

For example, 4! = 4 * 3 * 2 * 1 = 24. 3! = 3 * 2 * 1 = 6. Set k = 3!, so k = (3 * 2 * 1). Thus, since 4! = 4 * 3 * 2 * 1, we see that we can replace the last part with k, such that 4! = 4k. We can easily expand this to fit any factorial where n is a natural number.

Rebootd
Yup