If x^0 is x/x, then Infinity^0 shall equal Infinity/Infinity!

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And then, what shall 0^0 be??

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0?
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x?
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Clue:

If 1/infinity is 0, then what would 0^0 be??

However it is true that 0 does not equal 1/infinity.

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The Answer is 0/0 for 0^0

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The answer is nemo
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Not neo
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I understand your reasoning, but it is not correct. The expression “x^0” is equal to 1 for any non-zero value of x. Therefore, Infinity^0 is also equal to 1. The expression “Infinity/Infinity” is undefined because it is an indeterminate form. Similarly, “0/0” and “Infinity/0” are also indeterminate forms.

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The value of 0^0 is undefined and can lead to contradictions in mathematics. There are different conventions for defining 0^0, depending on the context. In algebra and combinatorics, 0^0 is typically defined as 1

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EmberCrystal wrote:

I understand your reasoning, but it is not correct. The expression “x^0” is equal to 1 for any non-zero value of x. Therefore, Infinity^0 is also equal to 1. The expression “Infinity/Infinity” is undefined because it is an indeterminate form. Similarly, “0/0” and “Infinity/0” are also indeterminate forms.

Any non 0, number x, raised to the power of 0 is x/x. First and foremost principally.

That is why for non 0 -x, x^0 is 1. Because x/x is always 1, for non 0 or infinity x.

x^0 is 0/0 for 0-x, However.

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...
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You know, ima have you do my algebra homework sometime
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#10 whaaaaaatttttttt???!?!?!!?!!?!

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One_Zeroth wrote:
EmberCrystal wrote:

I understand your reasoning, but it is not correct. The expression “x^0” is equal to 1 for any non-zero value of x. Therefore, Infinity^0 is also equal to 1. The expression “Infinity/Infinity” is undefined because it is an indeterminate form. Similarly, “0/0” and “Infinity/0” are also indeterminate forms.

Any non 0, number x, raised to the power of 0 is x/x. First and foremost principally.

That is why for non 0 -x, x^0 is 1. Because x/x is always 1, for non 0 or infinity x.

x^0 is 0/0 for 0-x, However.

Updated!

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