Math problem I need help solving
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2 days ago
0
#4
It sounds like ur talking about a tesseract, which is unsolvable (I think) cuz its in the 4th dimension
2 days ago
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#5
I call it the “inscribed square” problem
This is an original name not based on another problem fr trust
This is an original name not based on another problem fr trust
2 days ago
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#8
Basically, s{1} is a unit square- a 1x1 square. S{x} is equal to the side lengths of it, so S{1}=1. S{2} is a square with its vertexes on the midpoints of the first square’s sides. It will have a side length of sqrt(0.5).
2 days ago
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#9
Ok I don’t think I’m explaining this well at some point I may make a yt vid where I try to better explain it
2 days ago
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#10
#8
Oh
I doubt there would be a limit in infinity, as it seems relatively simple of a problem
For question 1, I ain’t smart enough to make a problem for it, but i would assume it would be possible to make one (a quadratic should get the work done)
I have no clue what to do for question 2
Oh
I doubt there would be a limit in infinity, as it seems relatively simple of a problem
For question 1, I ain’t smart enough to make a problem for it, but i would assume it would be possible to make one (a quadratic should get the work done)
I have no clue what to do for question 2
2 days ago
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#12
😟 um I’m in 5th grade which grade is this?………. This looks so scary 😅😅😅
#1 jst used chat gpt
You lost me at the subscript thing, but it doesn't look that hard. I might look into it later today.
1: The area= s(x)=1/2^x
2: I don’t really understand this one. Are you asking for the side length of the next square developed inside the original one? If so it’s the original square’s side length x 0.7^ number of times the process described is repeated. I don’t think it’s very accurate, but it’ll hold up practically. If I knew trigonometry I’d probably be able to derive a precise equation for it.
3:I don’t think there are any. I can’t make a mathematical proof of this because it’s too advanced for my level.
RealTactics960 wrote:
Ok I don’t think I’m explaining this well at some point I may make a yt vid where I try to better explain it
Making a diagram would be better, although your problem is pretty easy to understand.
1 day ago
0
#20
Wouldn’t it be s(x)=1/2^(x-1)? (x=1 has an area of 1)
Also, I wanted to solve for the side length, not area, but since it’s a square, you could just do s(x)=sqrt(1/2^(x-1)), so I think we’ve solved it!
For 2, imagine taking every square and putting them one after the other, with the bottoms lined up. How long would the bottom line be? Using the solution above, I think it would be smth with sigma but I can’t type what it would be, lemme figure it out rq.
For 3, it’s a geometric progression, the absolute value of the common ration therefore has to be less than 1 to have a limit. Since it’s 1/2 for the area, it has a limit, but idk if it does for the actual one
Also, I wanted to solve for the side length, not area, but since it’s a square, you could just do s(x)=sqrt(1/2^(x-1)), so I think we’ve solved it!
For 2, imagine taking every square and putting them one after the other, with the bottoms lined up. How long would the bottom line be? Using the solution above, I think it would be smth with sigma but I can’t type what it would be, lemme figure it out rq.
For 3, it’s a geometric progression, the absolute value of the common ration therefore has to be less than 1 to have a limit. Since it’s 1/2 for the area, it has a limit, but idk if it does for the actual one
First, take a unit square (1x1). This is s{1} (the {} means subscript). Then, put a point at each of the four midpoints of s{1}’s sides and connect them to form a smaller square. This is s{2}. The pattern will continue infinitely.
Question 1: what is an equation that can allow you to solve for s{x}?
Question 2: what is an equation that allows you to solve for the summation of the side lengths of every point up to s{x}?
Question 3: what is the limit as this approaches infinity, if there is one?
(I’ll try to explain what I mean if this is confusing)